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lidiya [134]
3 years ago
7

Phân biệt các đặc điểm khác nhau giữa chất rắn, chất lỏng

Physics
1 answer:
vitfil [10]3 years ago
6 0

Answer:

şen çal kapimi turkish drama

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17. Which of the following is NOT a testable
Artemon [7]

Answer:

c. testing student opinions

Explanation:

opinions aren't factual and they would not aide an experiment if it wasn't for a social experiment.

7 0
2 years ago
4. A car is accelerating at 40 m/s2, if the car is 400 kg how much force
Ksenya-84 [330]
Sorry I’m only in kindergarten is it 10kg must be supplied???
5 0
3 years ago
A ball is thrown horizontally at a speed of 24 meters per second from the top of a cliff. if the ball hits the ground 4.0 second
Viktor [21]

Answer:

78.4 m

Explanation:

To obtain the height of the cliff;

We can use the Relation to obtain the final velocity, v

v = u + at

a = acceleration due to gravity = 9.8m/s²

v = 0 + (9.8*4)

v = 0 + 39.2

v = 39.2 m/s

To obtain the Height, S

v² = u² + 2aS

39.2^2 = 0 + 2(9.8)S

39.2^2 = 0 + 19.6S

1536.64 = 19.6S

S = 1536.64 / 19.6

S = 78.4 m

8 0
2 years ago
A 50 kg laboratory worker is exposed to 30 mJ of neutron radiation with an RBE of 10. Part A What is the dose in mSv
lys-0071 [83]

Answer:

The dose is 6 mSV

Explanation:

The absorbed dose (in gray - Gy) is the amount of energy that ionizing radiation deposits per unit mass of tissue. That is,

Absorbed dose = Energy deposited / Mass

while Dose equivalent (DE) (in Seivert -Sv) is given by

DE = Absorbed dose × RBE (Relative biological effectiveness)

First, we will determine the Absorbed dose

From the question, Energy deposited = 30mJ and Mass = 50kg

From,

Absorbed dose = Energy deposited / Mass

Absorbed dose = 30mJ/50kg

Absorbed dose = 0.6 mGy

Now, for the Dose equivalent (DE)

DE = Absorbed dose × RBE

From the question, RBE = 10

Hence,

DE = 0.6mGy × 10

DE = 6 mSv

5 0
3 years ago
A football coach sits on a sled while two of his players build their strength by dragging the sled across the field with ropes.
Jobisdone [24]

Answer:

F=507.7N

Explanation:

According to Newton's second law:

\sum F=m.a

in this case, the football players need to drag the coach at a constant velocity, thus means with no acceleration, so:

\sum F=0\\\\-F_f+F_p*cos(\theta)=0\\\\

there are 20 degrees between the two ropes that means each player exerts a force 10 degrees from the zero reference.

F_p=2*F\\\\F=\frac{1000N}{2*cos(10)}\\\\F=507.7N

5 0
3 years ago
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