A vibrating tuning fork of frequency 512 Hz is held over a water column with one end closed and the other open. As the water lev
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Answer:
T = 676 N
Explanation:
Given that: f = 65 Hz, L = 2.0 m, and ρ = 5.0 g = 0.005 kg
A stationary wave that is set up in the string has a frequency of;
f =
⇒ T = 4M
Where: t is the tension in the wire, L is the length of the wire, f is the frequency of the waves produced by the wire and M is the mass per unit length of the wire.
But M = L × ρ = (2 × 0.005) = 0.01 kg/m
T = 4 × ×
× 0.01
= 4 × 4 ×4225 × 0.01
= 676 N
Tension of the wire is 676 N.
8.15m. La altura de la casa de la cual se deja caer un objeto que tarda en caer es de 8.15m.
La clave para resolver este problema es mediante caída libre, la velocidad inicial del objeto es 0 por lo que podemos calcular la altura h de la casa mediante la relación .
Conocemos la gravedad y el tiempo en que tarda en caer el objeto
, sustituyendo los valores tenemos que: