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marysya [2.9K]
3 years ago
7

A vibrating tuning fork of frequency 512 Hz is held over a water column with one end closed and the other open. As the water lev

el is allowed to fall, a loud sound (resonance) is heard at specific water levels. Assume you start with the tube full of water, and begin steadily lowering the water level. What is the water level (as measured from the top of the tube) for the third such resonance?
Physics
1 answer:
aleksklad [387]3 years ago
8 0

Answer:

Explanation:

This is an example of resonance of air column with one end closed.

For third resonance , length of water column

= 5  x λ / 4

λ ( wave length ) = velocity / frequency

343 / 512

= .67 m

= 67 cm

length of air column

= 5 x λ / 4

= 5/4 x 67 cm

= 83.75 cm

water level will be 83.75 cm below.

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