1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
AnnyKZ [126]
3 years ago
15

Although it shouldn’t have happened, on a dive I fail to watch my SPG and run out of air. If my buddy is close by, my best optio

n is to __________. Another option is to _____________, if I’m in shallow water and the surface is closer than my buddy.
A ascend using my buddy's alternate air source / make a controlled emergency swimming ascent




B ascend using my buddy's alternate air source / make an buoyant emergency ascent




C make a normal ascent / ascend using my buddy's alternate air source




D make a controlled emergency swimming ascent / make a normal ascent
Physics
1 answer:
Airida [17]3 years ago
5 0

Answer:

A) ascend using my buddy's alternate air source / make a controlled emergency swimming ascent

Explanation:

When it is found that you are out of air while under water, first of all don't panic, look for your buddy. If you are unable to do that so, then you need to make an emergency ascent. First try to make a <u>Controlled Emergency Swimming Ascent</u> (CESA). This ascent remains under control and is performed at a safe ascent rate. As you ascend the air in your lungs will expand with decreasing ambient pressure. To avoid an over pressurization injury, always exhale a continuous string of bubbles while going up.

If you are not sure you will make to the surface that leading to inhale the only option is to turn the CESA into a Buoyant Emergency Ascent. To be ready locate your weight system as you ascend. As an addition remove the weight from one of weight pockets and hold it away from your body in preparation of dropping if necessary. Dropping the weight will give you an upward buoyant force which is an <u>uncontrolled buoyant emergency ascent</u> and <u><em>should be performed only as the last option</em></u>.

So, according to this, first, always have a look at your SPG. Then, if you are out of air, look for your buddy, if not found then make CESA and the last option will be buoyant emergency ascent.

You might be interested in
What is the acceleration along the ground of a 10 kg wagon when it is pulled with a force of 44 N at an angle of 35° above the
Olegator [25]

The acceleration of the wagon along the ground is 3.6 m/s².

To solve the problem above, we need to use the formula of acceleration as related to force and mass.

Acceleration: This can be defined as the rate of change of velocity.

⇒ Formula:

  • Fcos∅ = ma................. Equation 1

⇒ Where:

  • F = Force
  • ∅ = angle above the horizontal
  • m = mass of the wagon
  • a = acceleration of the wagon

⇒ make a the subject of equation 1

  • a = Fcos∅/m..................... Equation 2

From the question,

⇒ Given:

  • F = 44 N
  • ∅ = 35°
  • m = 10 kg

⇒ Substitute these values into equation 2

  • a = 44(cos35°)/10
  • a = 44(0.8191)/10
  • a = 3.6 m/s²

Hence, The acceleration of the wagon along the ground is 3.6 m/s²

Learn more about acceleration here: brainly.com/question/9408577

3 0
3 years ago
Calculate the wavelength of a photon having 3.26 x 10^-19 joules of energy
bekas [8.4K]
The energy of a photon is given by:
E=hf
where h is the Planck constant and f is the photon frequency.
We know the energy of the photon, E=3.26 \cdot 10^{-19} J, so we can rearrange the equation to calculate the frequency of the photon:
f= \frac{E}{h}= \frac{3.26 \cdot 10^{-19}J}{6.6 \cdot 10^{-34}Js}=4.94 \cdot 10^{14}Hz

And now we can use the following relationship between frequency f, wavelength \lambda and speed of light c to find the wavelength of the photon:
\lambda= \frac{c}{f}= \frac{3 \cdot 10^8 m/s}{4.94 \cdot 10^{14} Hz}=6.07\cdot 10^{-7} m=607 nm
8 0
3 years ago
What is the person’s displacement for the trip?<br><br> what is a vector quantity? give an example.
borishaifa [10]

Answer:

+ 3.0 m

Explanation:

displacement is shortest distance from fixed point O in particular direction . in diagram shortest distance at end from O is 3 m and it is right of O so +. HENCE +3.0m

4 0
3 years ago
A rocket fires two engines simultaneously. One produces a thrust of 725Ndirectly forward while the other gives a 513N thrust at
faust18 [17]

The magnitude of the resultant force, F = 1,190.3 acting at a direction X = 13.35°.

<h3>What is the resultant force the two engines exert on the rocket?</h3>

The resultant force on the rocket is calculated thus:

The 513N thrust is resolved into vertical and horizontal components;

Horizontal component: 513N cos(32.4°) = 433.14 N

Vertical component: 513N sin(32.4°) = 274.88 N

Total forward force on the rocket = 725 N + 433.14 N = 1,158.14 N

Total force at right angles:

0 + 274.88 N = 274.88 N

The resultant force (F) is then given as follows:

F² = a² + b²

F² = (1158.14 N)² + (274.88 N)²

F = √1,416,847.27

F = 1,190.3

To find the direction:

tan X 274.88 N / 1,158.14 N

X = tan⁻¹ 0.237346089419241

X = 13.35°

Therefore, the magnitude of the resultant force, F = 1,190.3 acting at a direction X = 13.35°.

In conclusion, the resultant force is obtained by resolving the forces into vertical and horizontal components.

Learn more about resultant force at: brainly.com/question/17434363

#SPJ1

8 0
2 years ago
How are electric motors and generators similar? 
kotykmax [81]

Answer:

they both produce energy

Explanation:

7 0
3 years ago
Other questions:
  • Which of these experiments would make use of quantitative data
    12·2 answers
  • If the graph shown is a position-time graph of an object moving at constant velocity, what is the velocity of the object? Assume
    8·1 answer
  • A negative charged particle of known magnitude q is placed in a uniform electric field of known strength E. What additional info
    11·1 answer
  • Explain why the baking instructions on a box of cake mix are different for high and low elevations. Would you expect to have a l
    14·1 answer
  • 1. a) If a particle's position is given by LaTeX: x\:=\:4-12t\:+\:3t^2x = 4 − 12 t + 3 t 2(where t is in seconds and x is in met
    12·2 answers
  • a car moves at 12m/s and coasts up a hill with a uniform acceleration of -1.6m/s2. how far has it traveled after 6.0s?
    13·1 answer
  • A boat is moving along the water. The forward thrust from the engines is 35,000 N. Water resistance is 20,000 N and air resistan
    10·1 answer
  • A 4-kg mass moving with speed 2 m/s, and a 2-kg mass moving with a speed of 4 m/s, are gliding over a horizontal frictionless su
    13·1 answer
  • A bullet that has been too badly mutilated to mark can be
    7·1 answer
  • A powerful missile reaches a speed of 5 kilometers per second in 10 seconds after its launch. What is the average acceleration o
    14·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!