Atoms are electrically neutral because they have equal numbers of protons (positively charged) and electrons (negatively charged).
For this problem we can use 2 equations.
(1) - E = mC²
E = Energy of photon (J)
m = Mass of photon (kg) (1.67x10⁻²⁷ kg)
C = speed of light (3 x 10⁸ m/s)
(2) - E = hf
E = Energy of photon (J)
h = plank's constant (6.63 × 10⁻³⁴<span>J s)
f = frequency of the photon (Hz)
(1) = (2)
hence, </span>mC² = fh
by rearranging,
f = mC² / h
f = 1.67x10⁻²⁷ kg * (3 x 10⁸ m/s)² / (6.63 × 10⁻³⁴J s)
f = 2.27 x 10²³ Hz
Answer : The temperature of gas is, 295 K
Explanation :
To calculate the temperature of gas we are using ideal gas equation:
where,
P = Pressure of gas = 1.21 atm
V = Volume of gas = 10.0 L
n = number of moles = 0.500 mole
R = Gas constant =
T = Temperature of gas = ?
Now put all the given values in above equation, we get:

Therefore, the temperature of gas is, 295 K
Answer:
is the solubility of
in 0.10 M
.
Explanation:
Concentration of calcium nitrate = ![[Ca(NO_3)_2]=0.10 M](https://tex.z-dn.net/?f=%5BCa%28NO_3%29_2%5D%3D0.10%20M)

![[Ca(NO_3)_2]=0.10 M=[Ca^{2+}]](https://tex.z-dn.net/?f=%5BCa%28NO_3%29_2%5D%3D0.10%20M%3D%5BCa%5E%7B2%2B%7D%5D)
Solubility product of the calcium fluoride = 
Solubility of calcium fluoride in calcium nitrate solution :

(0.10+S) (2S)
The expression of solubility is given by :
![K_{sp}=[Ca^{2+}][F^-]^2](https://tex.z-dn.net/?f=K_%7Bsp%7D%3D%5BCa%5E%7B2%2B%7D%5D%5BF%5E-%5D%5E2)

Solving for S:

is the solubility of
in 0.10 M
.