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Novosadov [1.4K]
4 years ago
7

A girl of mass 60 kg throws a ball of mass 0.8 kg against a wall. The ball strikes the wall horizontally with a speed of 11 m/s,

and it bounces back with this same speed. The ball is in contact with the wall for 0.05 s. What is the average force exerted on the wall by the ball?
A. 6600 N
B. 26,400 N
C. 13,200 N
D. 180 N
E. 350 N
Physics
1 answer:
True [87]4 years ago
5 0

Answer:

352 N

Explanation:

From Newton's second law of motion,

F = m(v-u)/t................ Equation 1

Where F = Average force exerted on the wall by the ball, m = mass of the ball, v = final velocity of the ball, u = initial velocity of the ball, t = time of contact of the ball with the wall.

From the question,

Assuming: The direction of the initial velocity to be negative

Given: m = 0.8 kg, u = -11 m/s, v = 11 m/s (bounce back with the same speed), t = 0.05 s

Substitute into equation 1

F = 0.8[11-(-11)]/0.05

F = 0.8(11+11)/0.05

F = 0.8(22)/0.05

F = 352 N

Hence the average force = 352 N

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Answer:

1) In a concave mirror parallel rays falling on it converges at F and 2F.

Explanation:

Spherical mirrors can be used for magnification of images. There are basically two types of spherical mirrors and they are converging mirror and diverging mirrors. The converging mirrors are also termed as concave mirrors and its basic work is to converge or combine light rays coming from a larger distance to a single point. Mostly the light beams falling parallel to the principle axis of the concave mirror will be acting as parallel rays. And when these parallel rays fall on the mirror, the converging point can be the focal point of the mirror.

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Read 2 more answers
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