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beks73 [17]
3 years ago
8

Consider a merry-go-round that has the form of a disc with radius 5.5 m and mass 155 kg. If five children, each of mass 20 kg, s

it on the outer edge of the merry-go-round, what is the total moment of inertia?
Physics
1 answer:
Nataly [62]3 years ago
7 0

Answer:

I=5369.375

Explanation:

Given:

  • mass of merry go round, M=155\ kg
  • radius of merry go round, r=5.5\ m
  • mass of child, m=20\ kg

<u>Considering merry-go-round as a disk, its moment of inertia is given as:</u>

I_d=\frac{1}{2} M.r^2

I_d=0.5\times 155\times 5.5^2

I_d=2344.375\ kg.m^2

<u>Considering children as point masses, their moment of inertia is given as:</u>

I_C=5(m.r^2)

since there are 5 children

I_C=5\times20\times 5.5^2

I_C=3025\ kg.m^2

<u>Now, total moment of inertia:</u>

I=I_C+I_d

I=3025+2344.375

I=5369.375

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