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4 years ago

In a voltage-divider biased npn transistor, if the upper voltage-divider resistor (the one connected to VCC) opens:______.

Engineering

1 answer:

fomenos4 years ago

4 0

Answer:

The transistor goes into cutoff ( A )

Explanation:

In a voltage-divider biased npn transistor, if the upper voltage-divider resistor (the one connected to VCC) opens the transistor goes into cutoff

Voltage-divider biased npn transistor is a transistor that consists of some resistors and this resistors help to divide and distribute the voltage entering the transistor into its correct levels ( this is the most popular means of biasing a BJT transistor )

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kiruha [24]

Answer:

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Explanation:

given data

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put here value and we get L

L = $\dfrac{0.41\times 10^{-3}\times \dfrac{\pi}{4}\times (3.9\times 10^{-3})^2\times 106\times 10^9}{1660}$

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L = 0.312752 m

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amm1812

Answer:

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3 years ago

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Answer:

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