Answer:
56.2 mL
Explanation:
Given data
- Initial volume (V₁): 250 mL
- Initial pressure (P₁): 1.00 atm
- Final pressure (P₂): 4.45 atm
Assuming the gas has an ideal behavior, we can find the final volume using Boyle's law.
P₁ × V₁ = P₂ × V₂
V₂ = P₁ × V₁/P₂
V₂ = 1.00 atm × 250 mL/ 4.45 atm
V₂ = 56.2 mL
<h2>Let us derive empirical formula </h2>
Explanation:
We are given with compound C₆N₄O₁₀: mass percentage of all is :
For C = 12 x 6 /288=0.25%
For N= 14 x 4 /288=0.19%
For 0= 16 x 10/288=0.5%
The elements present are :
Atomic mass moles Simplest ratio rounding off
C 12 0.25/12=0.020 0.02/0.02=1 2
N 14 0.9/14=0.06 0.06/0.02=3 6
O 16 0.5/16=0.03 0.03/0.02=1.5 3
The empirical formula derived is : C₂n₆O₃
Answer:
hydration reaction
Explanation:
The type of reaction would be hydration reaction.
<u>Hydration reaction generally involves a chemical reaction of water with another reactant and in which the water ends up being converted to another product entirely. </u>
A good example of hydration reaction is the reaction between alkene and water leading to the production of alcohol.
⇄ 
Answer:
In order to be able to solve this problem, you will need to know the value of water's specific heat, which is listed as
c=4.18Jg∘C
Now, let's assume that you don't know the equation that allows you to plug in your values and find how much heat would be needed to heat that much water by that many degrees Celsius.
Take a look at the specific heat of water. As you know, a substance's specific heat tells you how much heat is needed in order to increase the temperature of 1 g of that substance by 1∘C.
In water's case, you need to provide 4.18 J of heat per gram of water to increase its temperature by 1∘C.
What if you wanted to increase the temperature of 1 g of water by 2∘C ?
This will account for increasing the temperature of the first gram of the sample by n∘C, of the the second gramby n∘C, of the third gram by n∘C, and so on until you reach m grams of water.
And there you have it. The equation that describes all this will thus be
q=m⋅c⋅ΔT , where
q - heat absorbed
m - the mass of the sample
c - the specific heat of the substance
ΔT - the change in temperature, defined as final temperature minus initial temperature
In your case, you will have
q=100.0g⋅4.18Jg∘C⋅(50.0−25.0)∘C
q=10,450 J
Answer:
0.00840
Explanation:
The computation of the mole fraction is as follow:
As we know that
Molar mass = Number of grams ÷ number of moles
Or
number of moles = Number of grams ÷ molar mass
Given that
Number of moles of CaI2 = 0.400
And, Molar mass of water = 18.0 g/mol
Now Number of moles of water is
= 850.0 g ÷ 18.0 g/mol
= 47.22 mol
And, Total number of moles is
= 0.400 + 47.22
= 47.62
So, Molar fraction of CaI2 is
= 0.400 ÷ 47.62
= 0.00840
