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asambeis [7]
3 years ago
7

Two positive charges are equal. Which has more electric potential energy?

Physics
2 answers:
Maurinko [17]3 years ago
8 0
<h2>Answer 1 with Explanation </h2>

Electric potential vitality is the vitality that is expected to move a charge against an electric field. You need more vitality to move a charge further in the electric field, yet in addition more vitality to move it through a more grounded electric field. Envision that you have a colossal contrarily charged plate, with a little emphatically charged molecule adhered to it through the electric power. There's an electric field around the plate that is pulling all emphatically charged items toward it (while pushing other adversely charged articles away). You take the positive molecule, and begin to pull it off the plate, against the draw of the electric field. It's diligent work, on the grounds that the electric power is pulling them together.

<h2>Answer 2 with Explanation </h2>

On the off chance that you let the positive molecule go, it would snap back to the negative plate, pulled by the electric power. The vitality that you used to move the molecule far from the plate is put away in the molecule as electrical potential vitality. The potential the molecule needs to move when it's given up. In the event that you pulled the positive molecule further far from the plate, you would need to utilize more vitality, so the charge would have increasingly electrical potential vitality put away in it. In the event that we multiplied the charge on the plate, once more, you would require more vitality to move the positive molecule. On the off chance that we multiplied the charge on the positive molecule, you would require more vitality to move it. You get the thought. Envision that rather than an adversely charged plate, our plate is decidedly charged. Our positive molecule would be pushed far from the plate since they are both decidedly charged. This time, we need to put in vitality to endeavor to draw the molecule nearer to the plate, rather than to pull it away. The closer we endeavor to move it to the plate, the more vitality we need to put in, so the more electrical potential energy the particle would have.

Xelga [282]3 years ago
7 0

Electrostatic potential energy of a system of charge is given by

U = \frac{kq_1q_2}{r}

here we have

q_1,q_2 = two charges of different magnitudes

r = distance between charges

so here we can see that electrostatic potential energy will depends upon the product of two charges and inversely depends upon the distance between the two charges

So here we can say that the electrostatic potential energy of two charges will be same and equal to each other

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The gravitational potential energy of a particle of mass m moving under the influence of a fixed mass M is given by - , where G
djverab [1.8K]

-GMm/2r is the total energy of the mass m if it is in a circular orbit about mass M.

Given

A particle of mass m moving under the influence of a fixed mass's M, gravitational potential energy of formula  -GMm/r, where r is the separation between the masses and G is the gravitational constant of the universe.

As the Gravity Potential energy of particle = -GMm/r

Total energy of particle = Kinetic energy + Potential Energy

As we know that

Kinetic energy = 1/2mv²

Also, v is equals to square root of GM/r

v = √GM/r

Put the value of v in the formula of kinetic energy

We get,

Kinetic Energy = GMm/2r

Total Energy = GMm/2r + (-GMm/r)

                     = GMm/2r - GMm/r

                     = -GMm/2r

Hence, -GMm/2r is the total energy of the mass m if it is in a circular orbit about mass M.

Learn more about Gravitational Potential Energy here brainly.com/question/15896499

#SPJ4

3 0
1 year ago
A 1500kg car traveling at 25m/s skids to a stop. The force of friction between the tires and the road is 10500N. How far does th
ale4655 [162]

44.64m

Explanation:

Given parameters:

Mass of the car = 1500kg

Initial velocity = 25m/s

Frictional force = 10500N

Unknown:

Distance moved by the car after brake is applied = ?

Solution:

The frictional force is a force that  opposes motion of a body.

To solve this problem, we need to find the acceleration of the car. After this, we apply the appropriate motion equation to solve the problem.

     -Frictional force = m x a

the negative sign is because the frictional force is in the opposite direction

m is the mass of the car

 a is the acceleration of the car

    a = \frac{frictional force}{mass} = \frac{10500}{1500} = -7m/s²

Now using;

   V² = U² + 2as

   V is the final velocity

   U is the initial velocity

   a is the acceleration

   s is the distance moved

  0² = 25² + 2 x 7 x s

  0 = 625 - 14s

  -625 = -14s

      s = 44.64m

   

learn more:

Velocity problems brainly.com/question/10932946

#learnwithBrainly

7 0
3 years ago
Physics Circuit, need a walkthrough
QveST [7]
I don't see a picture
7 0
3 years ago
A sensational 130 kg midfielder has 695 J of
antoniya [11.8K]

Answer:

v = 3.27 m/s

Explanation:

KE = 1/2 mv^2

695 J = 1/2 (130kg)(v^2)

695 J / (1/2 x 130kg) = v^2

v^2 = square root of 10.69

v = 3.27 m/s

4 0
3 years ago
What happens when a wave encounters a boundary and then goes back to the original medium?
lawyer [7]
It causes a movement of convection in the water resulting in a pulling current.

Hope this helpss
7 0
3 years ago
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