A Fruit Stand sells 6 oranges for $3.00 and grapefruit for $2.40 people buy 10 oranges and 11 grapefruits much does the fruit sp

Question

malfutka [58]

3 years ago

5

A Fruit Stand sells 6 oranges for $3.00 and grapefruit for $2.40 people buy 10 oranges and 11 grapefruits much does the fruit sp

end

Mathematics

2 answers:

kotykmax [81] · Answer 1 · 2022-05-28T21:57:22+03:00

The correct answer is:

$31.40.

Explanation:

Since 6 oranges cost $3.00, we can divide to find the cost of one orange:

3.00/6 = $0.50. Each orange costs $0.50.

If ten oranges are bought, this would cost 10(0.50)=$5.00.

Each grapefruit costs $2.40; 11 of them would cost 11(2.40) = 26.40.

Together the total cost is $5+$26.40 = $31.40.

kykrilka [37] · Answer 2 · 2022-05-28T23:16:08+03:00

Answer:

$31.4

Step-by-step explanation:

Given –

Cost of 6 oranges = $3.00

Cost of 1 grapefruit = $2.40

Cost of 1 orange = $3.00/6

= $0.5

People bought 10 oranges and 11 grapefruits.

Cost of 10 oranges = 10 x cost of one orange

= 10 x $0.5

= $ 5

Cost of 11 grapefruit = 11 x cost of one grapefruit

= 11 x $2.4

= $26.4

So total cost of 10 oranges and 11 grapefruits

= $ 5 + $26.4

= $31.4