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juin [17]
3 years ago
9

Two kids are playing tag. The first kid is running at an unknown speed chasing the other. The first kid has a mass of 25 kg and

a KE of 450 J.
How fast is the first kid running?
I really need help
Physics
1 answer:
Monica [59]3 years ago
3 0

Answer:

1mph

Explanation:

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Câu 1. Con lắc lò xo treo thẳng đứng, dao động điều hòa với biên độ 2cm và tần số góc 20 rad/s. Chiều dài tự nhiên của lò xo là
natka813 [3]

Answer:

28 cm and 32 cm

Explanation:

1. The spring pendulum hangs vertically, oscillates harmonic with amplitude 2cm and angular frequency 20 rad/s. The natural length of

a spring is 30cm. What is the minimum and maximum length of the spring during the oscillation? Take g = 10m/s2.

As the amplitude is 2 cm and the natural length is 30 cm. So, it oscillates between 30 -2 = 28 cm to 30 + 2 = 32 cm.

So, the minimum length is 28 cm and the maximum length is 32 cm.

8 0
3 years ago
You are In-line skates at the top of a small hill. Your potential energy is equal to 1000 J. The last time we checked, your mass
stira [4]

A) <u>Weight = mass × acceleration (due to gravity)  </u>

= 60×9.8  

= 588 N  

<u>B) Potential energy = mass x gravity x change in height </u>

1,000 = 60.0 x 9.8 x h

h =  1.7 m      

<u>C) Kinetic energyF = potential energyI </u>

KEF = 1/2mv2  

PEI = mgh = 1,000 J

1/2mv2 = 1,000

1/2(60.0)v2 = 1,000  

v2 = 33.33

v = 5.77 m/s

3 0
3 years ago
In what scientific study did scientists discover that when atoms split they _________.
Shtirlitz [24]

Answer:OOF

Explanation:

6 0
3 years ago
Directions: Select ALL the correct answers.
nordsb [41]
Definitely D. The brakes on a bike rub against the wheel. Not sure about the others.
5 0
3 years ago
A uniform-density 7 kg disk of radius 0.21 m is mounted on a nearly frictionless axle. Initially it is not spinning. A string is
GREYUIT [131]

Answer:

\omega = 22.67 rad/s

Explanation:

Here we can use energy conservation

As per energy conservation conditions we know that work done by external source is converted into kinetic energy of the disc

Now we have

W = \frac{1}{2}I\omega^2

now we know that work done is product of force and displacement

so here we have

W = F.d

W = (44 N)(0.9 m) = 39.6 J

now for moment of inertia of the disc we will have

I = \frac{1}{2}mR^2

I = \frac{1}{2}(7 kg)(0.21^2)

I = 0.154 kg m^2

now from above equation we will have

39.6 = \frac{1}{2}(0.154)\omega^2

\omega = 22.67 rad/s

5 0
3 years ago
Read 2 more answers
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