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Alchen [17]
2 years ago
5

Determine the mass of CO2 produced by burning enough of methane to produce 1.50×102kJ of heat. CH4(g)+2O2(g)→CO2(g)+2H2O(g)ΔH∘rx

n=−802.3kJ Express your answer using three significant figures.
Chemistry
1 answer:
MArishka [77]2 years ago
8 0

<u>Answer:</u> The mass of CO_2 produced will be 8.228 g.

<u>Explanation:</u>

We need to find the mass of carbon dioxide produced when 150 kJ of heat is released.

For the given chemical reaction:

CH_4(g)+2O_2(g)\rightarrow CO_2(g)+2H_2O(g);\Delta H^o_{rxn}=-802.3kJ

By Stoichiometry of the reaction:

802.3 kJ of energy is released when 1 mole of carbon dioxide is produced.

So, 150 kJ of energy will be release when = \frac{1}{802.3}\times 150=0.187mol of carbon dioxide is produced.

To calculate the mass of carbon dioxide, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Moles of carbon dioxide gas = 0.187 mol

Molar mass of carbon dioxide gas = 44 g/mol

Putting values in above equation, we get:

0.187mol=\frac{\text{Mass of carbon dioxide gas}}{44g/mol}\\\\\text{Mass of carbon dioxide gas}=8.228g

Hence, the mass of CO_2 produced will be 8.228 g.

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Write the net ionic equation for the following molecular equation Mg (s) +Snso (aq) Mgso4 (aq) Sn(s) Use the lowest possible coe
Simora [160]

Answer:

Mg(s) + Sn²⁺(aq) ⇄ Mg²⁺(aq) + Sn(s)

Explanation:

Let's consider the following molecular equation.

Mg(s) + SnSO₄(aq) ⇄ MgSO₄(aq) + Sn(s)

The full ionic equation includes al the ions and the species that do not dissociate in water.

Mg(s) + Sn²⁺(aq) + SO₄²⁻(aq) ⇄ Mg²⁺(aq) + SO₄²⁻(aq) + Sn(s)

The net ionic equation includes only the ions that participate in the reaction (not spectator ions) and the species that do not dissociate in water.

Mg(s) + Sn²⁺(aq) ⇄ Mg²⁺(aq) + Sn(s)

3 0
3 years ago
Two samples of the same compound are compared. what does the data represent? sample 1: 24.22 g carbon and 32.00 g oxygen sample
goblinko [34]

According to law of definite proportion:

In a compound, elements are always arranged in fixed ratio by mass.

Here, sample 1 has 23.22 g Carbon and 32.00 g Oxygen.

Converting mass into number of moles:

Molar mass of carbon is 12 g/mol and that of oxygen is 16 g/mol thus,

n_{C}=\frac{m_{C}}{M_{C}}=\frac{24.22 g}{12 g/mol}\approx 2 mol

Similarly, number of moles of oxygen will be:

n_{O}=\frac{m_{O}}{M_{O}}=\frac{32 g}{16 g/mol}=2 mol

The ratio of number of moles of carbon and oxygen will be:

C:O=n_{C}:n_{O}=2:2=1:1

Therefore, formula of compound will be CO.

Sample 2:

It has 36.22 g Carbon and 48.00 g Oxygen.

Converting mass into number of moles:

Molar mass of carbon is 12 g/mol and that of oxygen is 16 g/mol thus,

n_{C}=\frac{m_{C}}{M_{C}}=\frac{36.22 g}{12 g/mol}\approx 3 mol

Similarly, number of moles of oxygen will be:

n_{O}=\frac{m_{O}}{M_{O}}=\frac{48 g}{16 g/mol}=3 mol

The ratio of number of moles of carbon and oxygen will be:

C:O=n_{C}:n_{O}=3:3=1:1

The formula of compound will be CO.

Therefore, it is proved that carbon and oxygen are present in fixed ratios in both the samples.


4 0
2 years ago
HELP When 400 J of heat is added to 5.6 g of olive oil at 23*C, the temperature increases to 87*C. What is the specific heat of
babunello [35]

Q=mc*temperature change

400=5.6/1000*c*(87-23)

c=1160.07J/kg/k

4 0
3 years ago
How many moles are in 155 grams of aluminum
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Answer:

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Explanation:

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8 0
3 years ago
To make 340mL of a 0.4 M solution of Lici, how many mL of a 8 M solution should be used?
ioda

Answer:

Volume is the quantity of three-dimensional space enclosed by a closed surface, for example, the space that a substance (solid, liquid, gas, or plasma) or shape occupies or contains. Volume is often quantified numerically using the SI derived unit, the cubic metre.

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