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Alchen [17]
2 years ago
5

Determine the mass of CO2 produced by burning enough of methane to produce 1.50×102kJ of heat. CH4(g)+2O2(g)→CO2(g)+2H2O(g)ΔH∘rx

n=−802.3kJ Express your answer using three significant figures.
Chemistry
1 answer:
MArishka [77]2 years ago
8 0

<u>Answer:</u> The mass of CO_2 produced will be 8.228 g.

<u>Explanation:</u>

We need to find the mass of carbon dioxide produced when 150 kJ of heat is released.

For the given chemical reaction:

CH_4(g)+2O_2(g)\rightarrow CO_2(g)+2H_2O(g);\Delta H^o_{rxn}=-802.3kJ

By Stoichiometry of the reaction:

802.3 kJ of energy is released when 1 mole of carbon dioxide is produced.

So, 150 kJ of energy will be release when = \frac{1}{802.3}\times 150=0.187mol of carbon dioxide is produced.

To calculate the mass of carbon dioxide, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Moles of carbon dioxide gas = 0.187 mol

Molar mass of carbon dioxide gas = 44 g/mol

Putting values in above equation, we get:

0.187mol=\frac{\text{Mass of carbon dioxide gas}}{44g/mol}\\\\\text{Mass of carbon dioxide gas}=8.228g

Hence, the mass of CO_2 produced will be 8.228 g.

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Unlike the sun, the moon orbits the Earth. This is the reason why we see the <em>different phases of the moon.</em> The reflection of the moon is being illuminated back to us with the help of the sun. So, as the moon circles the Earth, we only see parts of the lit side. Such changes helps us see the moon in different phases such as<em> </em>the <em>Third Quarter, Crescent, New Moon, Full Moon, etc.</em>

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Kf = 2,3·10⁶ 1/s.
K = 4,0·10⁸ 1/s.
Kr = ?
Kf - <span>forward rate constant.
K - </span><span>equilibrium constant.
Kr - </span><span>reverse rate constant.
</span>Since both Kf and Kr are constants at a given temperature, their ratio is also a constant that is equal to the equilibrium constant K.<span>
K = Kf/Kr.
Kr = Kf/K = </span>2,3·10⁶ 1/s ÷ 4,0·10⁸ 1/s = 5,75·10⁻¹.

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