Answer:
a) 1.875 volts
b) 5.86 W
Explanation:
Given data:
transmission line resistance = 0.30/cable
power of the generator = 250 kW
if Vt = 80 kV
<u>a) Determine the decrease V along the transmission line </u>
Rms current in cable = P / Vt = 250 / 80 = 3.125 amps
hence the rms voltage drop ( Δrmsvoltage )
Δrmsvoltage = Irms* R = 3.125 * 2 * 0.30 =<em> 1.875 volts </em>
<u>b) Determine the rate Pd at which energy is dissipated in line as thermal energy </u>
Pd =
= 3.125^2 * 2* 0.30 = <em>5.86 W</em>