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3 years ago

Identify two simple machines in this compound machine. A. screw, lever B. screw, incline plane C. double pulley D. lever, pulley

Physics

2 answers:

seropon [69]3 years ago

5 0

It's A, the Screw leaver

irinina [24]3 years ago

3 0

Answer: correct option is (A) screw and lever.

Explanation :

Machines make our work easier. There are many types of simple machines i.e. lever, pulley, wheel and axle, screw, inclined plane and wedge.

In the given picture, there are two simple machines as screw and lever.

Nutcracker, stapler, tongs and tweezers are the example of lever.

Examples of use of screw are in a jar lid and ballpoint pens.

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You drop two balls of equal diameter from the same height at the same time. Ball 1 is made of metal and has a greater mass than

Lelechka [254]

Answer:

The drop time ball 1 is less than the drop time of ball 2. A further explanation is provided below.

Explanation:

The net force acting on the ball will be:

⇒ $F_{net}=mg-F_r$

Here,

F = Force

m = mass

g = acceleration

Now,

According to the Newton's 2nd law of motion, we get

⇒ $F_{net} = ma$

To find the value of "a", we have to substitute " $F_{net}=ma$ " in the above equation,

⇒ $ma=mg-F_r$

⇒ $a=g-\frac{F_r}{m}$

We can see that, the acceleration is greater for the greater mass of less for the lesser mass. Thus the above is the appropriate solution.

8 0

2 years ago

Read 2 more answers

15. यदि दिइएको केन्द्र 0 भएको वृत्तको

miv72 [106K]

Answer:

what language is that

Explanation:

i don't understand the languge u used please can you change it

8 0

2 years ago

A proton with a velocity in the positive x-direction enters a region where there is a uniform magnetic field B in the positive y

Genrish500 [490]

Answer:

Positive z direction.

Explanation:

The magnetic force acting on the electron is given by the formula as :

$F=q(v\times B)$

q is the charge on proton

v is the speed of proton

B is the magnetic field

It is mentioned that the proton is moving with a velocity in the positive x-direction. The uniform magnetic field B in the positive y-direction such taht,

q = +e

v = vi

B = Bj

$F=e(v\ i\times B\ j)$

Since, $i\times j=k$

$F=(evB)\ k$

So, the magnetic force acting on the proton in positive z axis. Hence, the correct option is (d) "positive z direction".

8 0

3 years ago

Consider a lawnmower of mass m which can slide across a horizontal surface with a coefficient of friction μ. In this problem the

inna [77]

Answer:

Fh = u*m*g / (cos(θ) - u*sin(θ))

Explanation:

Given:

- The mass of lawnmower = m

- The angle the handle makes with the horizontal = θ

- The force applied along the handle = Fh

- The coefficient of friction of the lawnmower with ground = u

Find:

Find the magnitude, Fh, of the force required to slide the lawnmower over the ground at constant speed by pushing the handle.

Solution:

- Construct a Free Body Diagram (FBD) for the lawnmower.

- Realize that there is horizontal force applied parallel to ground due to Fh that drives the lawnmower and a friction force that opposes this motion. We will use to Newton's law of motion to express these two forces in x-direction as follows:

F_net,x = m*a

- Since, the lawnmower is to move with constant speed then we have a = 0.

F_net,x = 0

- The forces as follows:

Fh*cos(θ) - Ff = 0

Where, Ff is the frictional force:

Fh = Ff /cos(θ)

Similarly, for vertical direction y the forces are in equilibrium. Using equilibrium equation in y direction we have:

- W - Fh*sin(θ) + Fn = 0

Where, W is the weight of the lawnmower and Fn is the contact force exerted by the ground on the lawnmower. Then we have:

Fn = W + Fh*sin(θ)

Fn = m*g + Fh*sin(θ)

The Frictional force Ff is proportional to the contact force Fn by:

Ff = u*Fn

Ff = u*(m*g + Fh*sin(θ))

Substitute this expression in the form derived for Fh and Ff:

Fh*cos(θ) = u*(m*g + Fh*sin(θ))

Fh*(cos(θ) - u*sin(θ)) = u*m*g

Fh = u*m*g / (cos(θ) - u*sin(θ))

5 0

3 years ago

WHAT THE HECK PLEASE HELP HURRY

Angelina_Jolie [31]

i dont know about this but im willing to help you even im a questioneer....

<h2>last choice:blocks 1,2 and 3</h2>

<h3>-questioneer </h3>

comment down below if you know anything about this and explain me so that i can answer it properly

4 0

3 years ago