Answer:
1. T₁ = 500 N
2. T₂ = 866 N
Explanation:
Please see attached photo for the diagram.
Thus, we can obtain obtained the value of T₁ and T₂ as follow:
1. Determination of T₁
Angle θ = 30
Hypothenus = 100 kg
Opposite = T₁ =?
Sine θ = Opposite /Hypothenus
Sine 30 = T₁ / 100
Cross multiply
T₁ = 100 × Sine 30
T₁ = 100 × 0.5
T₁ = 50 Kg
Multiply by 10 to express in Newton
T₁ = 50 × 10
T₁ = 500 N
2. Determination of T₂
Angle θ = 60
Hypothenus = 100 kg
Opposite = T₂ = ?
Sine θ = Opposite /Hypothenus
Sine 60 = T₂ / 100
Cross multiply
T₂ = 100 × Sine 60
T₂ = 100 × 0.8660
T₂ = 86.6 Kg
Multiply by 10 to express in Newton
T₂ = 86.6 × 10
T₂ = 866 N
Answer:
A) a_c = 1.75 10⁴ m / s², B) a = 4.43 10³ m / s²
Explanation:
Part A) The relation of the test tube is centripetal
a_c = v² / r
the angular and linear variables are related
v = w r
we substitute
a_c = w² r
let's reduce the magnitudes to the SI system
w = 4000 rpm (2pi rad / 1 rev) (1 min / 60s) = 418.88 rad / s
r = 1 cm (1 m / 100 cm) = 0.10 m
let's calculate
a_c = 418.88² 0.1
a_c = 1.75 10⁴ m / s²
part B) for this part let's use kinematics relations, let's start looking for the velocity just when we hit the floor
as part of rest the initial velocity is zero and on the floor the height is zero
v² = v₀² - 2g (y- y₀)
v² = 0 - 2 9.8 (0 + 1)
v =√19.6
v = -4.427 m / s
now let's look for the applied steel to stop the test tube
v_f = v + a t
0 = v + at
a = -v / t
a = 4.427 / 0.001
a = 4.43 10³ m / s²
Answer:
convection currents is the answer
The Force need to accelerate the object is by 3 m/s² is 15 N. Suppose a friction force of 5 N acts on the motion of the object, the force needed to be applied to the object is 20 N
<h3>Force:</h3>
This can be defined as the product of the mass and the acceleration of a body. The S.I unit of force is kgm/s or Newton(N)
To calculate the force needed to accelerate a mass of 5 kg object at 3 m/s² we use the formula below.
Formula:
- F = ma........ equation 1
Where:
- F = Net force needed to accelerate the object
- m = mass of the object
- a = acceleration of the object
From the question,
Given:
Substitute these values into equation 1
Suppose a frictional force of 5 N acts on the motion, The force applied is
- F = F'+ma............ Equation 2
Where:
- F = Frictional force = 5N
Substitute into equation 2
- F = 5(3)+5
- F' = 15+5
- F = 20 N.
Hence, The Force need to accelerate the object is by 3 m/s² is 15 N. Suppose a friction force of 5 N acts on the motion of the object, the force needed to be applied to the object is 20 N
Learn more about force here: brainly.com/question/12970081
