Question

What is the energy range (in eV) of photons of wavelength 410 nm to 750 nm ? Express your answers using two significant figures separated by a comma.

Answer 1

Explanation:

It is given that,

Wavelength 1, $\lambda_1=410\ nm=410\times 10^{-9}\ m$

Wavelength 2, $\lambda_2=750\ nm=750\times 10^{-9}\ m$

Energy of a photon having wavelength 1 is given by :

$E=\dfrac{hc}{\lambda}$

$E_1=\dfrac{6.62\times 10^{-34}\times 3\times 10^8}{410\times 10^{-9}}$

$E_1=4.84\times 10^{-19}\ J$

Energy of a photon having wavelength 2 is given by :

$E=\dfrac{hc}{\lambda}$

$E_2=\dfrac{6.62\times 10^{-34}\times 3\times 10^8}{750\times 10^{-9}}$

$E_2=2.64\times 10^{-19}\ J$

Hence, this is the required solution.