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3 years ago

What is the equivalent resistance of a circuit that contains two 50.0 resistors connected in parallel with a 12.0 V battery?

Physics

2 answers:

Pachacha [2.7K]3 years ago

8 0

1/Re=1/R1 +1/R2= 2x1/R1=2/R1=2/R2=2/50=1/25
1/Re=1/25, so the answer is Re= 25

the answer is B. 25.0

sineoko [7]3 years ago

8 0

Answer:

the other person is right, the answer is 25.0

Explanation:

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How does the tide cycle affect erosion along a sea coast?

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The tides are a constant pulling and pushing against the land. Causing erosion.

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3 years ago

A fan connected to a 120-volt electrical system by an extension cord was worn through and exposed the bare, energized conductor,

kari74 [83]

Answer: the ladder

Explanation: since the energized conductor is already in contact with the ladder there by making electric current to flow. The base of the ladder is on the ground there by making the circuit to be complete and causing electrocution.

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2 years ago

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Describe how to make a position-time graph.

salantis [7]

Answer:

There's a video called Drawing Position vs Time Graphs made by MrDGenova that may help you, it's only three minutes long.

Explanation:

Hope that helps, if not, you could tell me what you don't understand and I could try explaining it in further detail.

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2 years ago

A 0.29 kg particle moves in an xy plane according to x(t) = - 19 + 1 t - 3 t3 and y(t) = 20 + 7 t - 9 t2, with x and y in meters

Artist 52 [7]

Answer:

Part a)

$F = 7.76 N$

Part b)

$\theta = -137.7 degree$

Part c)

$\theta = -127.7 degree$

Explanation:

As we know that acceleration is rate of change in velocity of the object

So here we know that

$x = -19 + t - 3t^3$

$y = 20 + 7t - 9t^2$

Part a)

differentiate x and y two times with respect to time to find the acceleration

$a_x = \frac{d^2}{dt^2}(-19 + t - 3t^3)$

$a_x = \frac{d}{dt}(0 +1 - 9t^2)$

$a_x = -18t$

$a_y = \frac{d^2}{dt^2}(20 + 7t - 9t^2)$

$a_y = \frac{d}{dt}(0 +7 - 18t)$

$a_y = -18$

Now the acceleration of the object is given as

$\vec a = (-18t)\hat i + (-18)\hat j$

at t= 1.1 s we have

$\vec a = -19.8 \hat i - 18 \hat j$

now the net force of the object is given as

$\vec F = m\vec a$

$\vec F = (0.29 kg)(-19.8 \hat i - 18 \hat j)$

$\vec F = -5.74 \hat i - 5.22 \hat j$

now magnitude of the force will be

$F = \sqrt{5.74^2 + 5.22^2} = 7.76 N$

Part b)

Direction of the force is given as

$tan\theta = \frac{F_y}{F_x}$

$tan\theta = \frac{-5.22}{-5.74}$

$\theta = -137.7 degree$

Part c)

For velocity of the particle we have

$v_x = \frac{dx}[dt}$

$v_x = (0 +1 - 9t^2)$

$v_y = \frac{dy}{dt}$

$v_y = (0 +7 - 18t)$

now at t = 1.1 s

$\vec v = -9.89\hat i - 12.8 \hat j$

now the direction of the velocity is given as

$\theta = tan^{-1}(\frac{v_y}{v_x})$

$\theta = tan^{-1}(\frac{-12.8}{-9.89})$

$\theta = -127.7 degree$

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3 years ago

What is the main function of the spongy bone'

storchak [24]

Oooooo there's a spongy bone? that's cool! Lol okay okay, I will research it and help you out.

Here's what I found:

Cancellous bone, also known as spongy or trabecular bone, is one of the two types of bone tissue found in the human body. ... It is very porous and contains red bonemarrow, where blood cells are made.

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3 years ago

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