Question

A tank of water has a length 10.0 m, width 5.00 m, and depth 2.50 m. What the absolute pressure at the bottom of the tank?

Answer 1

Answer:

1.28 x 10^5 Pa

Explanation:

The absolute pressure at the bottom of the tank of water is given by:

$p= p_0 + \rho g h$

where

$p_0 = 1.03 \cdot 10^5 Pa$ is the atmospheric pressure

$\rho = 1000 kg/m^3$ is the water density

g = 9.8 m/s^2 is the acceleration of gravity

h = 2.50 m is the heigth of the column of water

Substituting into the formula, we find

$p=1.03\cdot 10^5 +(1000)(9.8)(2.50)=1.28\cdot 10^5 Pa$