Answer:
w/v% = gm per 100 ml
75gm X gm 7500
------- = ------ == --------
1500ml 100ml 1500X
X=5%
Explanation:
In a Brønsted-Lowry acid-base reaction, a conjugate acid is the species formed after the base accepts a proton. By contrast, a conjugate base is the species formed after an acid donates its proton.
Proton = H⁺
This means for the molecules that requires us to look for their conjugate bases, we simply remove a proton to it.
a. What are the conjugate bases of the molecules:
i C6H5OH : C6H5O⁻
ii. CH3-SH : CH3-S⁻
iii. CH3-CH2-CO2H : CH3-CH2-COO⁻
The molecules that requires us to look for their conjugate acids, we simply add a proton to it.
b. What are the conjugate acids of the molecules:
i. CH3–(CH2)-CO2- : i. CH3–(CH2)-COOH
ii. CH3–(CH2)-NH2 : ii. CH3–(CH2)-NH3⁺
iii. Ring at right ?
The change is called evolution. They change when the organism adapts to the environment and passes the genes to the offsprings.
Answer:
Isotope N–14 = 99%
Isotope N–15 = 1%
Explanation:
Let isotope A be N-14
Let isotope B be N-15
From the question given above, the following data were obtained:
For isotope A (N-14):
Mass of A = 14
Abundance of A = A%
For isotope B (N-15):
Mass of B = 15
Abundance of B = (100 – A%)%
Atomic mass of nitrogen = 14.01 amu
Thus, we can obtain the relative abundances of the naturally occurring isotopes of nitrogen as illustrated below:
Atomic mass = [(Mass of A × A%)/100] + [(Mass of B × B%)/100]
14.01 = [(14 × A%)/100] + [(15 × (100 – A%)/100]
14.01 = 0.14A% + 0.15(100 – A%)
14.01 = 0.14A% + 15 – 0.15A%
Collect like terms
14.01 – 15 = 0.14A% – 0.15A%
– 0.99 = – 0.01A%
Divide both side by – 0.01
A% = – 0.99 / –0.01
A% = 99%
Abundance of B = (100 – A%)%
Abundance of B = (100 – 99)%
Abundance of B = 1%
Thus, the relative abundances of the naturally occurring isotopes of nitrogen are:
Isotope N–14 = 99%
Isotope N–15 = 1%