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nataly862011 [7]
2 years ago
5

An 1825 kg car is moving to the right at a constant speed of 1.24 m/s. What is the net force on the car?

Physics
2 answers:
bagirrra123 [75]2 years ago
7 0

Answer:

net force is 0

Explanation:

as acceleration is zero, net force equals to zero

irakobra [83]2 years ago
6 0

<u>Statement</u><u>:</u>

An 1825 kg car is moving to the right at a constant speed of 1.24 m/s.

<u>To </u><u>find </u><u>out:</u>

The net force on the car.

<u>Solution:</u>

  • Here, it is given in the statement that the car is moving with constant speed.
  • We know, acceleration is the change in speed within a time period.
  • Since, here the speed is constant, so there is no change of speed.
  • Therefore, there is no acceleration.

  • We know, force = mass × acceleration

  • Therefore, net force on the car
  • = 1825 × 0
  • = 0

<u>Answer</u><u>:</u>

<u>The </u><u>net </u><u>force </u><u>on </u><u>the </u><u>car </u><u>is </u><u>0</u><u>.</u>

Hope you could understand.

If you have any query, feel free to ask.

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Answer:

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Explanation:

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\vec v_{H} = \vec v_{W}+\vec v_{H/W} (1)

In addition, vectors in rectangular form are defined by the following expression:

\vec v = \|\vec v\| \cdot (\cos \alpha, \sin \alpha) (2)

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\|\vec v\| - Magnitude, measured in meters per second.

\alpha - Direction angle, measured in sexagesimal degrees.

Then, (1) is expanded by applying (2):

\vec v_{H} = \|\vec v_{W}\| \cdot (\cos \alpha_{W},\sin \alpha_{W}) +\|\vec v_{H/W}\| \cdot (\cos \alpha_{H/W},\sin \alpha_{H/W}) (3)

\vec v_{H} = \left(\|\vec v_{W}\|\cdot \cos \alpha_{W}+\|\vec v_{H/W}\|\cdot \cos \alpha_{H/W}, \|\vec v_{W}\|\cdot \sin \alpha_{W}+\|\vec v_{H/W}\|\cdot \sin \alpha_{H/W} \right)

If we know that \|\vec v_{W}\| = 25\,\frac{m}{s}, \|\vec v_{H/W}\| = 125\,\frac{m}{s}, \alpha_{W} = 240^{\circ} and \alpha_{H/W} = 325^{\circ}, then the resulting velocity of the helicopter is:

\vec v_{H} = \left(\left(25\,\frac{m}{s} \right)\cdot \cos 240^{\circ}+\left(125\,\frac{m}{s} \right)\cdot \cos 325^{\circ}, \left(25\,\frac{m}{s} \right)\cdot \sin 240^{\circ}+\left(125\,\frac{m}{s} \right)\cdot \sin 325^{\circ}\right)\vec v_{H} = \left(89.894\,\frac{m}{s}, -93.348\,\frac{m}{s}\right)

The resultant velocity of the helicopter is \vec v_{H} = \left(89.894\,\frac{m}{s}, -93.348\,\frac{m}{s}\right).

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Answer:

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