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2 years ago

An 1825 kg car is moving to the right at a constant speed of 1.24 m/s. What is the net force on the car?

Physics

2 answers:

bagirrra123 [75]2 years ago

7 0

Answer:

net force is 0

Explanation:

as acceleration is zero, net force equals to zero

irakobra [83]2 years ago

6 0

Statement:

An 1825 kg car is moving to the right at a constant speed of 1.24 m/s.

To find out:

The net force on the car.

Solution:

Here, it is given in the statement that the car is moving with constant speed.
We know, acceleration is the change in speed within a time period.
Since, here the speed is constant, so there is no change of speed.
Therefore, there is no acceleration.

We know, force = mass × acceleration

Therefore, net force on the car
= 1825 × 0
= 0

Answer:

The net force on the car is 0.

Hope you could understand.

If you have any query, feel free to ask.

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A confined aquifer with a porosity of 0.15 is 30 m thick. The potentiometric surface elevation at two observation wells 1000 m a

AlekseyPX

Answer:

Part (a) The flow rate per unit width of the aquifer is 1.0875 m³/day

Part (b) The specific discharge of the flow is 0.0363 m/day

Part (c) The average linear velocity of the flow is 0.242 m/day

Part (d) The time taken for a tracer to travel the distance between the observation wells is 4132.23 days = 99173.52 hours

Explanation:

Part (a) the flow rate per unit width of the aquifer

From Darcy's law;

$q = -Kb\frac{dh}{dl}$

where;

q is the flow rate

K is the permeability or conductivity of the aquifer = 25 m/day

b is the aquifer thickness

dh is the change in th vertical hight = 50.9m - 52.35m = -1.45 m

dl is the change in the horizontal hight = 1000 m

q = -(25*30)*(-1.45/1000)

q = 1.0875 m³/day

Part (b) the specific discharge of the flow

$V = \frac{Q}{A} = \frac{q}{b} = -K\frac{dh}{dl}\\\\V = -(25 m/d).(\frac{-1.45 m}{1000 m}) = 0.0363 m/day$

V = 0.0363 m/day

Part (c) the average linear velocity of the flow assuming steady unidirectional flow

Va = V/Φ

Φ is the porosity = 0.15

Va = 0.0363 / 0.15

Va = 0.242 m/day

Part (d) the time taken for a tracer to travel the distance between the observation wells

The distance between the two wells = 1000 m

average linear velocity = 0.242 m/day

Time = distance / speed

Time = (1000 m) / (0.242 m/day)

Time = 4132.23 days

$= 4132.23 days *\frac{24 .hrs}{1.day} = 99173.52, hours$

4 0

3 years ago

Scientist accept ideas of the past and do not try to revise or change them

Vikentia [17]

Is this a question or a statement. This statement would be incorrect.

4 0

3 years ago

8. If the mass of a balloon is 300 kg and the lift force provided by the atmosphere is 3300 N, what

zmey [24]

Answer:

Toward the north, 300 N

Explanation:

Consider the upward direction as positive and downward direction as negative.

Given:

Mass of the balloon is, $m=300\ kg$

Lift force on the balloon in the upward direction is, $F_L=3300\ N$

Take acceleration due to gravity as 10 N/kg.

Now, weight of the balloon acting downward is given as the product of its mass and acceleration due to gravity. Therefore,

Weight is, $W=mg=(300\ kg)(10\ N/kg)=-3000\ N$

Now, net force is given as the vector sum of both the forces.

$F_{net}=F_L+W\\F_{net}=3300-3000=300\ N(\textrm{Upward direction})$

The upward direction is the direction of North. So, the net force acting on the balloon is 300 N towards North.

3 0

3 years ago

The strings in a compound bow behave approximately like a

Pepsi [2]

The speed at which the arrow would be launched is 133.42 m/s

The work-energy theorem asserts that the net work done applied by the forces on a particular object is equivalent to the change in its kinetic energy.

The equation for the work-energy theorem can be computed as:

$\mathbf{W =\Delta K.E}$

$\mathbf{F\Delta x =\dfrac{1}{2} mv^2}$

where;

Force (F) = 267 N
distance Δx = 0.60 m
mass (m) = 18 g
speed (v) = ???

From the above equation, let make speed(v) the subject of the formula:

∴

$\mathbf{v = \sqrt{\dfrac{2(F \Delta x)}{m}} }$

$\mathbf{v = \sqrt{\dfrac{2(267 \times 0.60)}{0.018}} }$

v = 133.42 m/s

Learn more about the work-energy theorem here:

brainly.com/question/17081653

7 0

2 years ago

for a moving object distance covered by it is always greater than or equal to the displacement of the object in a given time. ex

AleksandrR [38]

<h3>Answer</h3>

Distance is equal to the Total Distance covered by a body, from the initial till the final point $.$

Displacement is equal to the shortest distance between two points.

So we known that Distance can only be equal to or greater than the displacement and can never be shorter than the displacement.

This is just common sense how can anything be shorter than the shortest path itself. But it can be equal to the shortest path

☯ Distance is a scalar quantity and has only magnitude but no direction.

☯ Displacement is a vector quantity and has both magnitude and direction.

☯ Distance can only have +ve values whereas displacement can be +ve, -ve or even be zero.

6 0

3 years ago