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3 years ago

13

The balls in the image above have different masses and speeds. Rank them in terms of momentum, from least to greatest.

3 answers:

Elden [556K]3 years ago

4 0

C A D B

is the correct order

Hope this helps :/

N76 [4]3 years ago

3 0

The momentum of an object is equivalent to the product of the object's mass and velocity. Computing the momentum for each ball:
A- 15 * 0.7 = 10.5
B- 5.5 * 1.2 = 6.6
C- 5.0 * 2.5 = 12.5
D- 1.5 * 5.0 = 7.5

Therefore, ball C has the greatest momentum.

stupidchild2 years ago

0 0

bdac

this is the answer

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Describe the motion of the car as it moved across the floor

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It moves horizontally across the floor.

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3 years ago

Experimenting with free fall, Mariana observes that her baseball takes 1.5 s to travel the last 30m before hitting the ground. F

Art [367]

Answer:

37.8 m

Explanation:

At point 0, the ball is at height y₀.

At point 1, the ball is at height 30 m.

At point 2, the ball is at height 0 m.

Given:

y₁ = 30 m

y₂ = 0 m

v₀ = 0 m/s

a = -10 m/s²

t₂ − t₁ = 1.5 s

Find: y₀

Use constant acceleration equation.

y = y₀ + v₀ t + ½ at²

Evaluate at point 1.

y₁ = y₀ + v₀ t₁ + ½ at₁²

30 m = y₀ + (0 m/s) t₁ + ½ (-10 m/s²) t₁²

30 = y₀ − 5t₁²

Evaluate at point 2.

y₂ = y₀ + v₀ t₂ + ½ at₂²

0 m = y₀ + (0 m/s) t₂ + ½ (-10 m/s²) t₂²

0 = y₀ − 5t₂²

y₀ = 5t₂²

Substitute:

y₀ = 5 (1.5 + t₁)²

y₀ = 5 (2.25 + 3t₁ + t₁²)

y₀ = 11.25 + 15t₁ + 5t₁²

30 = 11.25 + 15t₁ + 5t₁² − 5t₁²

30 = 11.25 + 15t₁

t₁ = 1.25

30 = y₀ − 5t₁²

30 = y₀ − 5(1.25)²

y₀ ≈ 37.8

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3 years ago

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3 years ago

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A spring with spring constant 15 N/m hangs from the ceiling. A ball is attached to the spring and allowed to come to rest. It is

Lana71 [14]

Answer:

a

$m = 0.169 \ kg$

b

$|v_{max} |= 0.5653 \ m/s$

Explanation:

From the question we are told that

The spring constant is $k = 14 \ N/m$

The maximum extension of the spring is $A = 6.0 \ cm = 0.06 \ m$

The number of oscillation is $n = 30$

The time taken is $t = 20 \ s$

Generally the the angular speed of this oscillations is mathematically represented as

$w = \frac{2 \pi}{T}$

where T is the period which is mathematically represented as

$T = \frac{t}{n}$

substituting values

$T = \frac{20}{30 }$

$T = 0.667 \ s$

Thus

$w = \frac{2 * 3.142 }{ 0.667}$

$w = 9.421 \ rad/s$

this angular speed can also be represented mathematically as

$w = \sqrt{\frac{k}{m} }$

=> $m =\frac{k }{w^2}$

substituting values

$m =\frac{ 15 }{(9.421)^2}$

$m = 0.169 \ kg$

In SHM (simple harmonic motion )the equation for velocity is mathematically represented as

$v = - Awsin (wt)$

The velocity is maximum when $wt = \(90^o) \ or \ 1.5708\ rad$

$v_{max} = - A* w$

=> $|v_{max} |= A* w$

=> $|v_{max} |= 0.06 * 9.421$

=> $|v_{max} |= 0.5653 \ m/s$

5 0

3 years ago