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Zielflug [23.3K]
3 years ago
9

Rutherford's scattering experiments gave the first indications that an atom consists of a small, dense, positively charged nucle

us surrounded by negatively charged electrons. His experiments also allowed for a rough determination of the size of the nucleus. In this problem, you will use the uncertainty principle to get a rough idea of the kinetic energy of a particle inside the nucleus.
Consider a nucleus with a diameter of roughly 5.0×10−15 meters.

Part A

Consider a particle inside the nucleus. The uncertainty Δx in its position is equal to the diameter of the nucleus. What is the uncertainty Δp of its momentum? To find this, use ΔxΔp≥ℏ2where ℏ=h2π.

Express your answer in kilogram-meters per second to two significant figures.

You did not open hints for this part.

ANSWER:

Δp = kg⋅m/s
Physics
1 answer:
Varvara68 [4.7K]3 years ago
4 0

The uncertainty on the momentum is 1.1\cdot 10^{-20} kg m/s

Explanation:

We can solve the problem by using the uncertainty principle, which states that:

\Delta x \Delta p \geq \frac{h}{4\pi}

where

\Delta x is the uncertainty on the position

\Delta p is the uncertainty on the momentum

h=6.63\cdot 10^{-34} Js is the Planck constant

For the nucleus in this problem, the uncertainty on the position is equal to the size of the nucleus, therefore

\Delta x = 5.0\cdot 10^{-15} m

Therefore we can substitute into the equation and solve for \Delta p to find the uncertainty on the momentum:

\Delta p \geq \frac{h}{4\pi \Delta x}=\frac{6.63\cdot 10^{-34}}{4\pi (5.0\cdot 10^{-15})}=1.1\cdot 10^{-20} kg m/s

Learn more about momentum:

brainly.com/question/7973509

brainly.com/question/6573742

brainly.com/question/2370982

brainly.com/question/9484203

#LearnwithBrainly

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Explanation:

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= 220 dv / dt

so applying newton's law

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v dm = 220 dv

dv / v = dm / 220

integrating on both sides

∫ dv / v    = ∫ dm / 220

lnv =  ( m₂ - m₁ ) / 220

ln4000 - ln 2500 = ( m₂ - m₁ ) / 220

( m₂ - m₁ ) = 220 x ( ln4000 - ln 2500 )

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4 years ago
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A solenoid coil with 22 turns of wire is wound tightly around another coil with 340 turns. The inner solenoid is 25.0 cm long an
LUCKY_DIMON [66]

Answer:

a) 1.34*10^-8 W

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I: current of the inner solenoid = 0.100A

A: area of the inner solenoid = pi*r^2

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You calculate the area and then replace the values of N, I, mu_o and A to find the magnetic flux:

A=\pi(10^{-2}m)^2=3.141510^{-4}m^2\\\Phi_B=(4\pi*10^{-7}T/A)(340)(0.100A)(3.1415*10^{-4}m^2)=1.34*10^{-8}W\\

the magnetic flux is 1.34*10^{-8}W

b) the mutual inductance is given by:

M=\mu_o N_1 N_2 \frac{A_2}{l}

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N2: turns of the inner solenoid

A_2: area of the inner solenoid

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by replacing all these values you obtain:

M=(4\pi*10^{-7}T/A)(340)(22)\frac{3.14*10^{-4}m^2}{0.25m}=1.18*10^{-5}H

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\epsilon_1=M\frac{dI_2}{dt}

by replacing you obtain:

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7 0
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Where R is the equivalent resistance of the resistors in series

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The power dissipated supplied to the motor is given by:

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a=\dfrac{d[8i+4tj+6k]}{dt}

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