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uysha [10]
3 years ago
12

Read the paragraph from the section "Colombian President Declares An Emergency."

Physics
1 answer:
Galina-37 [17]3 years ago
5 0

A  Many people who came to the hospital had very serious injuries.

Explanation:

From the passage, we can infer that many people who came to the hospital had very serious injuries.

Let us analyze the given options:

Many doctors were worried about the safety of their own families.

No where in the passage was the families of the Doctors mentioned. The passage directly spoke to the Doctors and their victims.

Many people were able to quickly leave the hospital after treatment.

There was shortage of blood and there was no way they could have been treated without it. The passage suggests an emergency situation was up.

Also, many people needed blood for treatment but there was an acute shortage. No way to treat and discharge them.

Many doctors who worked through the night wanted to go home.

Again, no text in the passage suggests this. We have a picture of Doctors who wanted to tend to their patients but lacked the means to do so.

<em>The fitting inference that can be drawn from the passage is that many people came to the hospital had serious injuries which led to blood shortage. </em>

learn more:

Emergency brainly.com/question/4496477

#learnwithBrainly

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1) First of all, let's find the resistance of the wire by using Ohm's law:
V=IR
where V is the potential difference applied on the wire, I the current and R the resistance. For the resistor in the problem we have:
R= \frac{V}{I}= \frac{5.70 V}{17.6 A}=0.32 \Omega

2) Now that we have the value of the resistance, we can find the resistivity of the wire \rho by using the following relationship:
\rho =  \frac{RA}{L}
Where A is the cross-sectional area of the wire and L its length.
We already have its length L=2.90 m, while we need to calculate the area A starting from the radius:
A=\pi r^2 = \pi (0.654\cdot 10^{-3}m)^2=1.34 \cdot 10^{-6}m^2

And now we can find the resistivity:
\rho =  \frac{RA}{L}= \frac{(0.32 \Omega)(1.34 \cdot 10^{-6}m^2)}{2.90m}=  1.48 \cdot 10^{-7}\Omega \cdot m
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3 years ago
a liquid with a specific heat of 1900J/Kg° C has 4750 joules of heat energy is added to it. if the temperature increases from 20
GREYUIT [131]
E=mcθ
where E is the energy added,m is the mass,c is the specfic heat capacity and θ is the change in temprature.
making m subject u get E/c<span>θ=m
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plugging the values  we get :
</span>\frac{4750}{1900*10}
<span>
solving it we get the answer that is 0.25kg or 250 grams

</span>
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Answer:

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Below is an attachment containing the solution

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