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ArbitrLikvidat [17]
3 years ago
6

Calculate the frequency of a wave with a wavelength of 8.00x10 m. In what region of the electromagneti spectrum is this?

Chemistry
1 answer:
zheka24 [161]3 years ago
7 0

<em>The frequency of the wave with a wavelength of is</em> <u>3.748 × 10 ⁶ /s</u>.

I attached the working and the answer to the question below. I hope I was able to help.

Please note that C = speed of light (2.998 × 10⁸ m/s), ν = frequency and λ= wavelength.



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They have different amounts of neutrons.

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I have this chemistry question and I’m really struggling to answer it. Can someone please help me figure out the steps &amp; the
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Explanation:

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How many grams are in 2.40 moles of sodium hydroxide (NaOH)?
Bogdan [553]

Answer:

96g

Explanation:

Given parameters:

Number of moles of NaOH = 2.4moles

Unknown:

Mass of NaOH = ?

Solution:

The mass of a substance given the number of moles can be found using the expression below;

     Mass of NaOH  = Number of moles x molar mass;

  Molar mass of NaOH  = 23 + 16 + 1 = 40g/mol

Now input the parameters and solve;

    Mass of NaOH  = 2.4 x 40  = 96g

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How do atoms form new substances?
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3 years ago
Calculate the density of air at 100 Deg C and 1 bar abs. Use the Ideal Gas Law for your calculation and give answer in kg/m3. Us
madam [21]

Answer:

d=0.92\frac{kg}{m^{3}}

Explanation:

Using the Ideal Gas Law we have PV=nRT and the number of moles n could be expressed as n=\frac{m}{M}, where m is the mass and M is the molar mass.

Now, replacing the number of moles in the equation for the ideal gass law:

PV=\frac{m}{M}RT

If we pass the V to divide:

P=\frac{m}{V}\frac{RT}{M}

As the density is expressed as d=\frac{m}{V}, we have:

P=d\frac{RT}{M}

Solving for the density:

d=\frac{PM}{RT}

Then we need to convert the units to the S.I.:

T=100^{o}C+273.15

T=373.15K

P=1bar*\frac{0.98atm}{1bar}

P=0.98atm

M=28.9\frac{kg}{kmol}*\frac{1kmol}{1000mol}

M=0.0289\frac{kg}{mol}

Finally we replace the values:

d=\frac{(0.98atm)(0.0289\frac{kg}{mol})}{(0.082\frac{atm.L}{mol.K})(373.15K)}

d=9.2*10^{-4}\frac{kg}{L}

d=9.2*10^{-4}\frac{kg}{L}*\frac{1L}{0.001m^{3}}

d=0.92\frac{kg}{m^{3}}

5 0
4 years ago
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