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3 years ago

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!

Physics

1 answer:

Sav [38]3 years ago

4 0

Hi again!

The correct answer for the kinetic energy of the car is 484,000 joules.

We can find this by using the formula. The formula for kinetic energy is $\frac{1}{2}$ m $v^{2} \\$

Knowing this we can fill in the formula using the info we were provided. Doing this we get: $\frac{1}{2}$ (2,000 · $22^{2}$ )

$22^{2}$ = 484

2,000 · 484 = 968,000

$\frac{1}{2}$ · 968,000 = 484,000

_______________________________

Question 9: Anthony has more power than Angel

We can see Anthony gets done with the same work quicker than Angel. But they did the same amount of work, just Anthony was quicker. Power is the rate at which work is done. Knowing this we can see the answer is Anthony has more power than Angel.

I hope those answers help u!

Good luck! :)

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What is (Fnet3)x, the x-component of the net force exerted by these two charges on a third charge q3

Pachacha [2.7K]

This question is incomplete, the complete question is;

Coulomb's law for the magnitude of the force F between two particles with charges Q and Q' separated by a distance d is

|FI = |QQ'I / d²

where K = 1/4π∈0, and

∈0 = 8.854 × 10⁻¹² C²/(N.m²) is the permittivity of free space.

Consider two point charges located on the x-axis:

one charge, q₁ = -18.5 nC, is located at

x₁ = -1.715m; the charge q₂ = 30.5 nC, is at the origin ( x₂=0 )

What is (Fnet3)x, the x-component of the net force exerted by these two charges on a third charge q₃ = 51.0 nC placed between q₁ and q₂ at x₃ = -1.085 m ?

Answer: (Fnet3)x = -3.3287 × 10⁻⁵ N

Explanation:

Given that;

Q₁ = -18.5 nC Q₃ = 51 nC Q₂ = 30.5 nC

x₁ = - 1.715m x₃ = - 1.085m x₂ = 0

Now

x - component of Net force on charge Q₃ is

(Fnet3)x = -K|Q₁I|Q₃I / r₁3² - -K|Q₂I|Q₃I / r₂3²

(Fnet3)x = -(9×10⁹)(51×10⁻⁹) [ 18.5 / ((-1.085 + 1.715)²) + (30.5 / (-1.085)² ] × 10⁻⁹

(Fnet3)x = -3.3287 × 10⁻⁵ N

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