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tester [92]
2 years ago
12

If your face is 62 cm in front of a plane mirror, where is the image of your face located?

Physics
2 answers:
klemol [59]2 years ago
7 0

\huge \mathrm{ Answer࿐ }

The correct option is :

\hookrightarrow 62 cm in back of the mirror

_____________________________

<h2>Explanation : </h2>

Plane mirror always make a virtual and erect Image which is as far from the mirror as the object is !

_____________________________

\mathrm{ \#TeeNForeveR}

timurjin [86]2 years ago
3 0

Answer:

62 cm is in front of the mirror

Explanation:

This is answers

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You have a stopped pipe of adjustable length close to a taut 62.0-cm, 7.25-g wire under a tension of 3910 N . You want to adjust
Ber [7]

Answer:

L = 6 cm

Explanation:

Second overtone of the wire is same as third harmonic

so its frequency is given as

f = \frac{3}{2L}\sqrt{\frac{T}{\mu}}

here we know that

\mu = \frac{M}{L}

\mu = \frac{7.25 \times 10^{-3}}{0.62}

\mu = 0.0117 kg/m

now we have

f = \frac{3}{2\times 0.62}\sqrt{\frac{3910}{0.0117}}

f = 1398.6 Hz

Now fundamental frequency of sound in a pipe is given as

f = \frac{v}{4L}

1398.6 = \frac{340}{4L}

L = 0.06 m

L = 6 cm

7 0
2 years ago
Which of the following would have an effect on an object's mass?
ICE Princess25 [194]
None of the above

mass is measurement of how much stuff in inside something.
if you freeze or heat an object, you merely change the state of the object. the mass is conserved.
if you change the elevation, nothing happens to the mass. the stuff will not leave the object.
so it is None of the above


8 0
2 years ago
FONTE: JBC w our tree to eat por Pirage B097 VO DED expleyo 2. How do you feel about it? (Are you happy? A little bit sad? Conte
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5 0
2 years ago
Pada setiap tumbukan berlaku hukum
sweet-ann [11.9K]
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2 years ago
a 15-nC point charge is at the center of a thin spherical shell of radius 10cm, carrying -22nC of charge distributed uniformly o
Aleks [24]

Answer:

A) E = 278925.62 N/C with direction; radially out.

B) E = 43048.47 N/C with direction radially out.

C) E = -3214.29 N/C with direction radially in.

Explanation:

From Gauss' Law, the Electric field for any spherically symmetric charge or charge distribution is the same as the point charge formula. Thus;

E = kQ/r²

where;

Q is the net charge within the distance r.

We are given the charge Q = 15-nC and

spherical shell of radius 10cm

A) The distance r = 2.2 cm = 0.022 m is between the surface and the point charge, so only the point charge lies within this distance and Q = 15 nC = 15 x 10^(-9) C

While k is coulombs constant with a value of 9 × 10^(9) N.m²/C²

E = ((9 x 10^(9) × (15 x 10^(-9)))/(0.022)²

E = 278925.62 N/C

This will be radially out ,since the net charge is positive.

B) The distance r = 5.6 cm = 0.056 m is between the surface and the point charge, so only the point charge lies within this distance and Q = 15 nC = 15 x 10^(-9) C

While k is coulombs constant with a value of 9 × 10^(9) N.m²/C²

E = ((9 x 10^(9) × (15 x 10^(-9)))/(0.056)²

E = 43048.47 N/C

This will be radially out ,since the net charge is positive.

C) The distance r = 14 cm = 0.14 m is outside the sphere so the "net" charge within this distance is due to both given charges. Thus;

Q = 15 nC - 22 nC

Q = -7 nC = -7 x 10^(-9) C

and;

E = (9 x 10^(9)*(-7 x 10^(-9))/(0.14)²

E = -3214.29 N/C

This will be radially in, since the net charge is negative. You can indicate this with a negative answer.

8 0
3 years ago
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