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saw5 [17]
3 years ago
12

Which of the following chemical formulas shows an ionic compound?

Chemistry
2 answers:
sveticcg [70]3 years ago
8 0
C. NaCl
sodium chloride is made up of metals and non metals
harina [27]3 years ago
4 0

Answer:

NaCI

Explanation: I TOOK THE TEST

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A gas bottle contains 8. 61×1023 oxygen molecules at a temperature of 359. 0 k. what is the thermal energy of the gas? (you migh
Cloud [144]

A gas bottle contains 8. 61×1023 oxygen molecules at a temperature of 359. 0 k then the thermal energy of the gas is 6.35KJ.

<h3>What is thermal energy? </h3>

Thermal energy is the energy contained within a system which is responsible for its temperature. Heat is also termed as flow of thermal energy.

Thermal energy is directly proportional to the temperature. As temperature increase thermal energy increases.

Given,

temperature = 395K

Number of oxygen molecules= 8.61 × 10^(23)

Firstly we will calculate the number of moles = N/A

where A is the avagadro number = 6.022 × 10^(23)

number of moles = 8.61 × 10^(23)/6.022 ×10^(23)

number of moles = 1.42moles

Using the energy equation,

E = 3/2 × nRT

where R is the gas constant = 8.314J/molK

E = 3/2 × 1.42 × 8.314 × 359

= 6357.4J

= 6.35KJ

Thus, we found that the thermal energy of the gas is 6.35KJ.

learn more about thermal energy:

brainly.com/question/2409175

#SPJ4

5 0
1 year ago
Which elements in the periodic table are metalloids or have semimetallic properties?
inessss [21]
B, As only are metalloids or have semimetallic properties.
3 0
3 years ago
Help ASAP If you know what to do comment if u don’t I’ll report you ! Points added
mylen [45]

Proton:

Positive

Found in Nucleus

Mass of 1 AMU

Neutron:

Neutral

Found in Nucleus

Mass of 1 AMU

 

Electron:

Negative

Found in orbitals

Mass of 0 AMU

5 0
3 years ago
How much heat was transferred from 50.0 g of water if the temperature of the water went from 30.0 ° C to 55.0 °? The specific he
Lena [83]

Answer:

Heat transfer = Q = 62341.6 J

Explanation:

Given data:

Heat transfer = ?

Mass of water = 50.0 g

Initial temperature = 30.0°C

Final temperature = 55.0°C

Specific heat capacity of water = 4.184 J/g.K

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 55.0°C -  30.0°C

ΔT = 25°C (25+273= 298 K)

Q = 50.0 g × 4.184 J/g.K ×298 K

Q = 62341.6 J

4 0
3 years ago
Which is the molar mass of BF3?
Eduardwww [97]
The answer is 67.82 g/mol
3 0
3 years ago
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