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2 years ago

Supposing you were in space in a weightless environment, would it require a force to set an object in motion

1 answer:

7 0

Yes. If your smartphone was floating in front of your face, motionless
relative to you, it would require a force to start it moving toward you or
away from you.

But there's no minimum force required. ANY force, no matter how small,
even smaller than the smallest force that you can imagine, would set it in
motion.

The thing is, though, that the smaller the force acting on it, the smaller
acceleration it would get, and the slower it would move away from where
it is.

So if, say, you wanted to send it across the crew compartment and over
to your sleeping bag on the wall, and you had all day to watch it mope
along over there, you might breathe on it, and the force of your breath
would set it in slow motion in that direction. But if you wanted to throw it
at your crewmate, you'd need to give it more force.

You might be interested in

Can an object have both kinetic energy and gravitational potential energy? Explain.

Wewaii [24]

Answer:

Yes

Explanation:

An object can be moving (have kinetic energy) and be elevated above the ground at the same time (and also have potential energy).

3 0

2 years ago

Consider a glider flying at 400 meters altitude, when suddenly all its static ports become blocked by volcanic ash. The pressure

Furkat [3]

Answer:

the airspeed indicated by the pitot-tube driven airspeed indicator is 91.23m/s

Explanation:

Pitot tube

$U = \sqrt{\frac{(p_t - p_s)2}{d} }$

U = velocity(m/s)

$p_t$ = stagnation pressure (pa)

$p_s$ = static pressure (pa)

d = fluid density(kg/m³)

$p_t = p_a_t_m + \frac{1}{2} dv^2$

v = true velocity

= 101325 + 1/2(1.225)(25)²

$p_t = 101,707.8125pa$

$p_s = 96,610pa$

d = 1.225kg/m³

$U = \sqrt{\frac{2(101,707.8125 - 96,610)}{1.225} } \\\\U = 91.23m/s$

the airspeed indicated by the pitot-tube driven airspeed indicator is 91.23m/s

5 0

3 years ago

1. Why should you use scientific notation when writing big numbers?

Fynjy0 [20]

Answer:

It helps the answer look clean. It also makes the work easier to work with.

Explanation:

Instead of writing a lot of zeros, all you have to do is add exponents to the number to show how much the decimal moved.

6 0

3 years ago

A coin and feather are dropped in a moon. what will fall earlier on ground.give reasons.if they are dropped in the earth,which o

Sergeeva-Olga [200]

Answer:

on the moon, they will fall at the time

on earth, the coin will fall faster to the ground

Explanation:

A coin and feather dropped in a moon experience the same acceleration due to gravity as small as 1.625 m/s², and because of the absence of air resistance both will fall at the same rate to the ground.

If the same coin and feather are dropped in the earth, they will experience the same acceleration due to gravity of 9.81 m/s² and because of the presence of air resistance, the heavier object (coin) will be pulled faster to the ground by gravity than the lighter object (feather).

4 0

3 years ago

A power plant produces 1000 MW to supply a city 40 km away. Current flows from the power plant on a single wire of resistance 0.

nikitadnepr [17]

Answer:

Current = 8696 A

Fraction of power lost = $\dfrac{80}{529}$ = 0.151

Explanation:

Electric power is given by

$P=IV$

where I is the current and V is the voltage.

$I=\dfrac{P}{V}$

Using values from the question,

$I=\dfrac{1000\times10^6 \text{ W}}{115\times10^3\text{ V}} = 8696 \text{ A}$

The power loss is given by

$P_\text{loss} = I^2R$

where R is the resistance of the wire. From the question, the wire has a resistance of $0.050\Omega$ per km. Since resistance is proportional to length, the resistance of the wire is

$R = 0.050\times40 = 2\Omega$

Hence,

$P_\text{loss} = \left(\dfrac{200000}{23}\right)^2\times2$

The fraction lost = $\dfrac{P_\text{loss}}{P}=\left(\dfrac{200000}{23}\right)^2\times2\div (1000\times10^6)=\dfrac{80}{529}=0.151$

3 0

3 years ago