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ser-zykov [4K]
2 years ago
14

Supposing you were in space in a weightless environment, would it require a force to set an object in motion

Physics
1 answer:
Jobisdone [24]2 years ago
7 0

Yes.  If your smartphone was floating in front of your face, motionless
relative to you, it would require a force to start it moving toward you or
away from you. 

But there's no minimum force required.  ANY force, no matter how small,
even smaller than the smallest force that you can imagine, would set it in
motion. 

The thing is, though, that the smaller the force acting on it, the smaller
acceleration it would get, and the slower it would move away from where
it is. 

So if, say, you wanted to send it across the crew compartment and over
to your sleeping bag on the wall, and you had all day to watch it mope
along over there, you might breathe on it, and the force of your breath
would set it in slow motion in that direction.  But if you wanted to throw it
at your crewmate, you'd need to give it more force.
  
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Answer:

it is 2.2 m

Explanation:

because he goes back 2.2 m so 4.4 minus 2.2 equals 2.2

6 0
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To warm 2.0 l of tea (d = 1.01 g/ml; sp. heat = a cook places a 500 g block of stone at a temperature of 200f into the teapot. a
IRISSAK [1]
Volume of tea V = 2.0L = 2000 mL density d = 1.01 g/ mL mass of tea m = V * d = 2000mL * 1.01g/mL = 2020 gWhen we assume that the tea was initially at 72, the final temperature of the tea in F is 91. 
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3 years ago
Phil is riding a scooter and pushes off the ground with his foot. this causes him to accelerate at 12 m /s. Phil weighs 600 N. h
Dvinal [7]

Answer:

734.16 kg m/s^{2}

Explanation:

The problem is asking for the Force of pushing off the ground.

  • The formula of Force is: F = mass x acceleration

Given = <em>Mass</em>: 600 newtons (N)

             <em>Acceleration</em>: 12 m/s^{2}

We have to convert the mass into kg first. Remember that <u>1 kg is equal to 9.80665 newtons.</u>

Let x be the<em> mass in newtons</em>.

Let's convert: \frac{1 kg}{9.80665 N} x \frac{x}{600 N} = \frac{600}{9.80665} = 61.18 kg

Phil's weight is 61.18 kg

Let's go back to finding the force.

F = m x a

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F = 734.16 kg m/s^{2}

7 0
2 years ago
Please help me:(
Lelechka [254]

Answer:B

Explanation:

I’m doing the same thing you are!

3 0
3 years ago
You are holding a string tied to a lamp post 15 m away. You pull the string so that it has a tension of 1.5 N and a mass density
Dvinal [7]

Answer:

Explanation:

Given that

L= 15 m

T= 1.5 N

μ =0.0045 kg/m

f= 4 Hz

We know that

Velocity in string V is given as

V=\sqrt{\frac{T}{\mu}}

Now putting the values in the above equation we get

V=\sqrt{\frac{1.5}{0.0045}}=18.25\ m/s

We know that

V= f λ

\lambda =\frac{V}{f}

\lambda =\frac{18.25}{4}=4.5 m

6 0
3 years ago
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