Answer: in water vapor hydrogen atoms are bonded to oxygen atoms. In a mixture of hydrogen and oxygen hydrogen atoms are bonded to hydrogen atoms and oxygen atoms are bonded to oxygen atoms.
Explanation:
The unit of measurement is best to estimate the volume of a juice box will be kilogram.
<h3>What is volume?</h3>
The capacity of a container like how much quantity of liquid can be filled in that container is called the volume.
The juice bottle is estimated by liter as it contains the liquid. The juice box is a solid cardboard with some volume into which juice bottles are kept. So, the weight will be shown in kilograms.
Thus, the unit of measurement is best to estimate the volume of a juice box will be kilogram.
Learn more about volume.
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Answer:
a. All the laboratory equipment given are very basic equipment used in all the laboratories. Name of each equipment is as follows:
- V refers to the tape measure.
- W refers to dropper.
- X refers to an inoculating loop.
- Y refers to a stopwatch.
- Z refers to the microscope.
b. Use of each laboratory equipment identified is:
- Tape measures (V) is used to measure the length of objects or distance in a laboratory.
- Dropper (W) is used to measure unit of drop required to dispensed as one drop or several drops in any experiment.
- Inoculating loop (X) is used by microbiologists to cultivate microbes on plates and retrieving an inoculum from a culture of microorganisms.
- Stopwatch (Y) is used to measure the time of any experiment.
- Microscope (Z) is used to magnify an object to look at it in detail.
A) <u>Weight = mass × acceleration (due to gravity) </u>
= 60×9.8
= 588 N
<u>B) Potential energy = mass x gravity x change in height
</u>
1,000 = 60.0 x 9.8 x h
h = 1.7 m
<u>C) Kinetic energyF = potential energyI
</u>
KEF = 1/2mv2
PEI = mgh = 1,000 J
1/2mv2 = 1,000
1/2(60.0)v2 = 1,000
v2 = 33.33
v = 5.77 m/s
Answer:
The focal length of the appropriate corrective lens is 35.71 cm.
The power of the appropriate corrective lens is 0.028 D.
Explanation:
The expression for the lens formula is as follows;

Here, f is the focal length, u is the object distance and v is the image distance.
It is given in the problem that the given lens is corrective lens. Then, it will form an upright and virtual image at the near point of person's eye. The near point of a person's eye is 71.4 cm. To see objects clearly at a distance of 24.0 cm, the corrective lens is used.
Put v= -71.4 cm and u= 24.0 cm in the above expression.


f= 35.71 cm
Therefore, the focal length of the corrective lens is 35.71 cm.
The expression for the power of the lens is as follows;

Here, p is the power of the lens.
Put f= 35.71 cm.

p=0.028 D
Therefore, the power of the corrective lens is 0.028 D.