Answer:
10m/s^2
Explanation:
Given data
velocity= 40m/s
time= 4 seconds
Acceleration a =????
We know that
a= velocity/time
substitute
a=40/4
a= 10m/s^2
Hence the acceleration will be 10m/s^2
Answer:
after it has hit the ground
Answer:
See explanation
Explanation:
We have a mass
revolving around an axis with an angular speed
, the distance from the axis is
. We are given:
![\omega = 10 [rad/s]\\r=0.5 [m]\\m=13[Kg]](https://tex.z-dn.net/?f=%5Comega%20%3D%2010%20%5Brad%2Fs%5D%5C%5Cr%3D0.5%20%5Bm%5D%5C%5Cm%3D13%5BKg%5D)
and also the formula which states that the kinetic rotational energy of a body is:
.
Now we use the kinetic energy formula

where
is the tangential velocity of the particle. Tangential velocity is related to angular velocity by:

After replacing in the previous equation we get:

now we have the following:

therefore:

then the moment of inertia will be:
![I = 13*(0.5)^2=3.25 [Kg*m^2]](https://tex.z-dn.net/?f=I%20%3D%2013%2A%280.5%29%5E2%3D3.25%20%5BKg%2Am%5E2%5D)
Answer a) is incorrect as sound does not travel in a vacuum.
Answer:
7772.72N
Explanation:
When u draw your FBD, you realize you have 3 forces (ignore the force the car produces), gravity, normal force and static friction. You also realize that gravity and normal force are in our out of the page (drawn with a frame of reference above the car). So that leaves you with static friction in the centripetal direction.
Now which direction is the static friction, assume that it is pointing inward so
Fc=Fs=mv²/r=1900*15²/55=427500/55=7772.72N
Since the car is not skidding we do not have kinetic friction so there can only be static friction. One reason we do not use μFn is because that is the formula for maximum static friction, and the problem does not state there is maximum static friction.