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Anna007 [38]
3 years ago
15

Cortisol (molecular weight 362.47 g/mole), one of the major steroid hormones, is a key factor in the synthesis of protein. Its p

rofound effect on the reduction of inflammation explains its use in the treatment of rheumatoid arthritis. Cortisol is 69.9% C, 8.34% H and 22.1 % O by mass. What is its molecular formula?
Chemistry
1 answer:
frez [133]3 years ago
5 0

The molecular formula of cortisol is C₂₁H₃₀O₅

Explanation:

To find the cortisol formula we use the following algorithm:

divide each element percentage by the atomic weight of the element

for carbon 69.9 / 12 = 5.83

for hydrogen 8.34 / 1 = 8.34

for oxygen 22.2 / 16 = 1.41

now the we divide the obtained numbers by the lowest one, which is 1.41

for carbon 5.83/ 1.41 ≈ 4

for hydrogen 8.34 / 1.41 ≈ 6

for oxygen 1.41 / 1.41 = 1

the empirical formula of cortisol is C₄H₆O

the molecular formula of cortisol is (C₄H₆O)ₓ

70x = 362.47

x = 362.47 / 70

x ≈ 5.2

carbon ≈ 5.2 × 4 ≈ 21

hydrogen = 5 × 6 = 30

oxygen = 5 × 1 = 5

The molecular formula of cortisol is C₂₁H₃₀O₅

Learn more about:

determining the molecular formula of a compound

brainly.com/question/13764849

#learnwithBrainly

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A 32.50-g sample of a solid is placed in a flask. Toluene, in which the solid is insoluble, is added to the flask so that the to
marysya [2.9K]

Answer:

The density of the solid is 1,316 g/mL

Explanation:

The weight of both Toluene and the solid insoluble is 58,68 g. And the weight of the solid is 32,50 g. Thus, weight of toluene is:

58,68 g - 32,50 g = 26,18 g of Toluene

To know how much volume that toluene occupy you must use density thus:

26,18 g of toluene × ( 1 mL / 0,864 g) = 30,30 mL of toluene

The volume of both Toluene and the solid is 55,00 mL and the volume of toluene is 30,30 mL. Thus, the volume of the solid is:

55,00 mL - 30,30 mL = 24,70 mL

Knowing both volume and weight it is possible to know the density thus:

32,50 g / 24,70 mL = 1,316 g/mL

I hope it helps!

8 0
3 years ago
calculate the ph of a 0.020 m carbonic acid solution, h2co3(aq), that has the stepwise dissociation constants ka1
fgiga [73]

The calculated pH is 3.79. therefore, the solution is acidic.

No, carbonic acid is not a strong acid. H2CO3 is a weak acid that dissociates into a proton (H+ cation) and a bicarbonate ion (HCO3- anion). This compound only partly dissociates in aqueous solutions.

H2 CO3    =    H (+) + HCO3(-)          Ka1 = 4.3 * 10^ -7

   0.06 - x              x          x

Ka1 = x^2 / (0.06 - x) = 4.3 * 10^ - 7

A low Ka => x << 0.06 => 0.06 -x ≈ 0.06

=> Ka1 ≈ x^2 / 0.06 => x^2 ≈ 0.06 * Ka1 = 0.06 * 4.3 * 10^-7

=> x ≈ √ [ 2.58 * 10 ^ -8] = 1.606 * 10^ - 4 = 0.0001606

Second dissociation

HCO3(-)    =   H (+) + CO3(2-)         Ka2 = 5.6 * 10^ - 11

0.0001606 - y            y             y

Ka2 ≈ y^2 / 0.0001606 => y = √ [0.0001606 * 5.6* 10^ -11]

y = 9.48 * 10^ -8

An acidic solution has a high concentration of hydrogen ions (H +start superscript, plus, end superscript), greater than that of pure water.

[H+] = x + y = 1.607 * 10^ -4

pH = - log [H+] = 3.79

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5 0
2 years ago
Which substance can be decomposed by a chemical change?<br> (1) Co (3) Cr(2) CO (4) Cu
kotykmax [81]
Answer: (2) CO

Co, Cr, and Cu are elements. Elements cannot be broken down by a chemical change, but compounds can. Since CO is a compound, it can be decomposed by a chemical change.
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3 years ago
A 25-mL solution of H2SO4 is completely neutralized by 18 mL of 1.0M NaOH. What is the concentration of the H2SO4?
Charra [1.4K]
There are several information's already given in the question. Based on the information's provided, the answer can be easily deduced.
V1 = 25 ml
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     = 0.025 liter
V2 = 18 ml
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M2 = 1.0 M
M1 = ?
Then
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From the above deduction, it can be easily concluded that the correct option among all the options that are given in the question is the first option or option "A". I hope that this is the answer that has actually come to your help.
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