1. CaCr2O7
2. Sodium sulfite
3. (NH4)2SO3
4. Copper (II) nitrite
Answer:
m H2(g) = 2.241 g H2(g)
Explanation:
- 2Al(s) + 3H2SO4(aq) → Al2(SO4)3(aq) + 3 H2(g)
limit reagent:
∴ Mw Al = 26.982 g/mol
∴ Mw H2SO4 = 98.0785 g/mol
⇒ n Al = (20 g Al)×(mol/26.982 g) = 0.7412 mol Al
⇒ n H2SO4 = ( 115 g H2SO4 )×(mol/98.0785 g) = 1.173 mol H2SO4
⇒ n H2 = (0.7412 mol Al)×(3 mol H2/ 2 mol Al) = 1.112 mol H2
∴ Mw H2 = 2.016 g/mol
⇒ g H2 = (1.112 mol H2)×(2.016 g/mol) = 2.241 g H2
Answer:
6.68 x 10^-4
Explanation:
131g ÷ 261.337g/mol = 0.5012685 moles
0.5012685 moles ÷ 750.0 liters =
0.5012685÷ 750.0=0.000668358
6.68 x 10^-4
Thermodynamically favored process are those processes that do not require any assistance from outside the system e.g water boils at 25 degrees. Thermodynamically unfavored processes require assistance from outside to induce the required change for example water doesn't freeze at 15 degrees and therefore for that to happen several factors in the system have to be modified to achieve this. Therefore, there is a possibility of companies to produce product by using thermodynamically unfavored process by inducing changes in the system to achieve desired change or modification.
If you have a hamster with short fur, what possible genotypes could the hamster have?
Answer: <u>FF or Ff </u>
Explanation:
If you have a hamster with short fur, what possible genotypes could the hamster have? FF or Ff . ... The mystery hamster was a genotype ff and the phenotype for long fur and the parents can create offspring that have long fur or short fur because they are heterozygous dominant.
next question
If you have a hamster with long fur, what possible genotypes could the hamster have?
Answer: <u>Ff or ff </u>
Explanation:
If you have a hamster with long fur, what possible genotypes could the hamster have? Ff or ff . ... The mystery hamster was a genotype ff and the phenotype for long fur and the parents can create offspring that have long fur or short fur because they are heterozygous dominant.