<span>The atoms or molecules attain enough kinetic energy to overcome any intermolecular attractions they have. Since there are no longer any attractive forces between the particles, they are free to drift away into space. The same sort of thing happens in ordinary evaporation, but only at the surface. </span>
Answer:
3. The temperatures of the two substances equalize.
Explanation:
- As two objects at different temperatures are placed in contact, heat is transferred from the warmer to the cooler object until the temperature of the two objects be the same.
- The amount of heat that is transferred from the warmer object is equal to the amount of heat that is transferred into the cooler object.
- This is in agreement with the law of conservation of energy.
- <em>So, the right choice is: 3. The temperatures of the two substances equalize. </em>
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Answer:
The correct option is: Carbonate ion < Carbon dioxide < Carbon monoxide
Explanation:
Bond energy is defined as the average energy needed to break a chemical covalent bond and signifies the strength of chemical covalent bond.
The bond strength of a covalent bond depends upon the <u>bond length and the bond order.</u>
Carbon monoxide molecule (CO) has two covalent bond and one dative bond. Bond order 2.6
Carbon dioxide (CO₂) has two carbon-oxygen (C-O) double bonds of equal length. Bond order 2.0
Carbonate ion (CO₃²⁻) has three C-O partial double bonds. Bond order 1.5
Also, the bond length is <u>inversely proportional to the bond order and bond strength.</u>
Therefore, <u>order of C-O bond length:</u> Carbon monoxide<Carbon dioxide<Carbonate ion
<u>Order of C-O bond order</u>: Carbonate ion<Carbon dioxide<Carbon monoxide
<u>Order of C-O bond strength or energy</u><u>: Carbonate ion<Carbon dioxide<Carbon monoxide</u>
i need help ls i thank its book 500 grams
Answer:
Answer D => E°(Mg°/Cu⁺²) = 0.34 + 2.37 = 2.71v
Explanation:
(Oxidation) => Mg°(s) => Mg⁺²(aq) + 2e⁻ E°(Mg°/Mg⁺²) = -2.37 v
(Reduction) => Cu⁺²(aq) + 2e⁻ => Cu°(s) E°(Cu⁺²/Cu°) = +0.34 v
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Net Rxn => Mg°(s) + Cu⁺²(aq) => Mg⁺²(aq) + Cu°(s)
Std Cell Potential (25°C/1Atm) = E°(Redn) = E°(Oxidn) = +0.34v - (-2.37v)
= 0.34v + 2.37v = 2.72v
