9514 1404 393
Answer:
D) No Solutions
Step-by-step explanation:
The lines have the same slope (-4), but different y-intercepts (3, 0), so they are parallel lines. There can be no values of x and y that satisfy both equations.
There are no solutions.
Answer:
112
Step-by-step explanation:
To find the least common multiple, we break the numbers down into prime factors
7 = 7
14 = 7*2
16 = 2*8 = 2*4*2 = 2*2*2*2
Then we take the largest number of times it appears in all the numbers
2 appears 4 times so we take take four 2's
7 appears 1 so we take one 7
LCM = 2*2*2*2*7
LCM = 112
Answer:
p> -4
Step-by-step explanation:
3p + 2 > -10
3p > -10 -2
p> -4
Answer:
Step-by-step explanation:
First confirm that x = 1 is one of the zeros.
f(1) = 2(1)^3 - 14(1)^2 + 38(1) - 26
f(1) = 2 - 14 + 38 - 26
f(1) = -12 + 38 = + 26
f(1) = 26 - 26
f(1) = 0
=========================
next perform a long division
x -1 || 2x^3 - 14x^2 + 38x - 26 || 2x^2 - 12x + 26
2x^3 - 2x^2
===========
-12x^2 + 28x
-12x^2 +12x
==========
26x -26
26x - 26
========
0
Now you can factor 2x^2 - 12x + 26
2(x^2 - 6x + 13)
The discriminate of the quadratic is negative. (36 - 4*1*13) = - 16
So you are going to get a complex result.
x = -(-6) +/- sqrt(-16)
=============
2
x = 3 +/- 2i
f(x) = 2*(x - 1)*(x - 3 + 2i)*(x - 3 - 2i)
The zeros are
1
3 +/- 2i
