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Yuliya22 [10]
3 years ago
10

—13 < -x+5< 8 iѕ -21 True or false?

Mathematics
1 answer:
Andrej [43]3 years ago
6 0
This is True I believe
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Write the smallest and the largest 5 - digit number using 1 ,2,3,4,5 only one which is divisble by 6
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Largest 5-digit number is 54312 and is divisible by 6. The smallest 5 digit number is 12,345 and it's not divisible by 6

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Factor completely. wait for photo
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Apparently there's no solution?? i tried solving it, and i also used a special calculator, but no solution came up
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Contest a radio station is giving every third caller a t shirt and every tenth caller a ceramic mug which caller will be the fir
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The 30th caller will receive both.
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On Monday, Anthony invited 2 friends to join his online group. The next day, the friends and Anthony
Luda [366]

Answer:

27!!! I understand it!

Step-by-step explanation:

Monday: 1 , 2 (Anthony and his 2 friends)

They EACH invited two friends!

Tuesday: Anthony: 2 Friend 1: 2 Friend 2: 2

The same!!

Wednesday: A: 2 F1: 2 F2: 2

THE SAME AGAIN!

Thrusday: A: 2 F1: 2 F2: 2

THE SAME AGAIN!!

Friday: A: 2 F1: 2 F2: 2

1 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 = 27  

Hope it helps!!

Please be kind to mark Brainliest

Thanks!!! ☺

6 0
3 years ago
Sally lives in City A and works for the department of transportation. She needs to inspect the weigh stations in each of four di
galben [10]

Answer:

She can visit the cities in 192 ways

Step-by-step explanation:

If Sally starts from city A and after going to 4 cities she returns to home,

then that can be in 4! = 24 ways. (permutation of 4 distinct objects)

If between the time she visits cities, she comes home once,

then cities can be visited in,

4! \times 3_{C_{1}} = 72 ways.  (permutation of 4      distinct objects  and choosing 1 gap among the 3 )

If between the time she visits cities, she comes home twice,

then cities can be visited in,

4! \times 3_{C_{2}} =72 ways. (permutation of 4 distinct objects and finding 2 gaps among the 3)

If between the time she visits cities, she comes home thrice,

then cities can be visited in,

4! \times 3_{C_{3}} = 24 ways. (permutation of 4 distinct objects and choosing 3 gaps among the 3)

Now, she can't come home more than thrice in between the time she visits cities (since there are 4 cities to visit only)

So, the number of ways she can visit cities = (24+ 72 + 72 + 24)

                                                                       = 192

6 0
3 years ago
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