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grandymaker [24]
4 years ago
8

Why might construction crews want to install pipes before the foundation is poured

Engineering
1 answer:
Crazy boy [7]4 years ago
3 0

The answer is choice C

Explanation:

As during construction ,the site is cleared for all debris before laying out the foundation. Even the sewer lines are dug out .

So it will be useful for the construction crews to  connect the pipes to the sewer lines before the foundation is poured.

But usually the steps take in construction activity is:- first the site is cleared for the foundation to be poured  and once the foundation wall is set , then all utilities , including plumbing and electrical activities are done.,

After this process is over, the city inspector comes to check whether the foundation has been laid down as per the code of construction.

Only after that the rest of the construction activity follows through.

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The device shown below contains 2 kg of water. The cylinder is allowed to fall 800 m during which the temperature of the water i
olganol [36]

Answer:

m_added = 2 kg

Explanation:

From the question, we are told that the cylinder is allowed to fall 800 m in height. Thus, the potential energy will be converted into heat energy which will increase the temperature of water .

Now, let the mass of the falling cylinder be denoted by "m1" and let h be the height of fall.

Thus;

Formula for potential energy = mgh

Thus, as said earlier it's converted to heat generated. So heat generated = m1gh

Now let's calculate the heat absorbed;

heat absorbed = (m2)cΔt

Where;

ΔT is change in temperature

c is specific heat of water .

m2 is mass of water

Heat absorbed = heat generated

Thus;

(m2)cΔt = m1gh

Δt = m1gh/(m2•c)

Now, in both cases of the water and cylinder, m1, g , h and c are constant

Thus, we have;

Δt = (m1gh/m2) × 1/c

Where;

(m1gh/m2) is denoted as a constant k.

Thus;

Δt = K/m

For the first experiment, we have;

m = 2 kg

Δt = 2.4

Thus;

2.4 = K/2

Multiply both sides by 2 to get;

K = 4.8

For the second experiment, we have;

Δt = 1.2

Also,we have seen that K = 4.8

Thus;

Δt = K/m

Thus;

1.2 = 4.8/m

m = 1.2

m = 4 kg

Thus,mass added is;

m_added = 4 - 2

m_added = 2 kg

6 0
3 years ago
Plz watch our you tube channel called addie nahoe. I got 8 subscribers. I need 10. Plz like and hit that nocation bell. Plz!!!!
ValentinkaMS [17]
Ight

Have a great day
8 0
3 years ago
Aspectos de las técnicas escultóricas
mel-nik [20]
Técnicas y materiales de escultura
Modelado de arcilla. Clay tiene muchas ventajas para un artista. ...
Modelado de cera. El modelado con cera permite a un artista crear un diseño único. ...
Esculpir. ...
Talla de madera. ...
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Fundición de bronce. ...
Decoración.


Corrígeme si estoy equivocada.. :)
3 0
3 years ago
Water at atmospheric pressure boils on the surface of a large horizontal copper tube. The heat flux is 90% of the critical value
zloy xaker [14]

Answer:

119.1°c

Explanation:

Temperature can be referred to as a measure of the warmth or coldness of an object or substance with reference to some standard value. The temperature of two systems is the same when the systems are in thermal equilibrium.

To determine the tube surface temperature immediately after installation and after prolonged service.

We will apply to appropriate formula, but first lets define the terms in the question.

Please kindly check attachment.

6 0
4 years ago
Oxygen enters an insulated 14.2-cm-diameter pipe with a velocity of 60 m/s. At the pipe entrance, the oxygen is at 240 kPa and 2
MatroZZZ [7]

Answer:

Entropy generation==0.12 KW/K

Explanation:

s_2-s_1=C_p\ln \frac{T_2}{T_1}-R\ln \frac{P_2}{P_1}

s_2-s_1=0.891\ln \frac{291}{293}-0.2598\ln \frac{200}{240}

s_2-s_1=0.0412\frac{KJ}{kg-K}

Mass flow rate= \rho\times\dfrac{\pi}{4}d^2V

\rho_1=\dfrac {P_1}{RT_1}

\rho_1=\dfrac {240}{0.2598\times 293}

\rho_1=3.51\frac{kg}{m^3}

mass flow rate=\rho_1A_1V_1

So by putting the values

Mass flow rate=2.97 kg/s

So entropy generation=(2.97)(0.0412)

                                    =0.12 KW/K

8 0
4 years ago
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