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algol [13]
3 years ago
10

The manufacturer of a 1.5 V D flashlight battery says that the battery will deliver 9 {\rm mA} for 37 continuous hours. During t

hat time the voltage will drop from 1.5 {\rm V} to 1.0 {\rm V} . Assume the drop in voltage is linear with time.Part A How much energy does the battery deliver in this 37h interval?Express your answer to two significant figures and include the appropriate units.
Engineering
1 answer:
borishaifa [10]3 years ago
7 0

Answer:

1.42 KJ

Explanation:

solution:

power in beginning p_{0}=(1.5 V).(9×10^{-3} A)

                                    = 13.5 mW

after continuous 37 hours it drops to

                                    p_{37}=(1 V).(9×10^{-3} A)

                                         =9 mW

When the voltage will drop energy will not remain the same but the voltage drop will always remain same if the voltage was drop to for example from 5 V to 4.5 V the drop will remain the same.

                  37 hours= 37.60.60

                                 =133200‬ s

                              w=(9×10^{-3} A×133200‬ )+\frac{1}{2}(13.5.10^{-3}-9.10^{-3})(133200)

                                 =1.42 KJ

<em>NOTE:</em>

There maybe a calculation error but the method is correct.

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What are the characteristic features of stress corrosion cracks?
Oduvanchick [21]

Answer and Explanation:

The crack formation growth that takes place in an environment corrosive.

Stress corrosion cracks can be defined as the spontaneous failures of the metal alloy as a result of the combined action of corrosion and high tensile stress.

Some of the characteristic features of stress corrosion cracks are:

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5 0
3 years ago
As resistors are added in series to a circuit, the total resistance will
olganol [36]

The equivalent of the resistance connected in the series will be Req=R₁+R₂+R₃.

<h3>
What is resistance?</h3>

Resistance is the obstruction offered whenever the current is flowing through the circuit.

So the equivalent resistance is when three resistances are connected in series. When the resistances are connected in series then the voltage is different and the current remain same in each resistance.

V eq    =    V₁    +    V₂    +    V₃

IReq    =    IR₁    +    IR₂   +    IR₃

Req    =    R₁    +    R₂   +    R₃

Therefore the equivalent of the resistance connected in the series will be Req=R₁+R₂+R₃.

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8 0
2 years ago
An electric field is expressed in rectangular coordinates by E = 6x2ax + 6y ay +4az V/m.Find:a) VMN if point M and N are specifi
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Answer:

a.) -147V

b.) -120V

c.) 51V

Explanation:

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b.) The problem becomes easier to solve if you draw out the circuit. Since potential at Q is 0, then Q is at ground. So voltage across V_MQ is the same as potential at V_M.

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Honestly, these things take practice to get used to. It's really hard to explain this.

3 0
3 years ago
In part A you are asked to write the pseudocode for the program. In part B you are asked to write the syntax of the code for the
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Answer:

C++.

Explanation:

#include <iostream>

#include <string>

using namespace std;

///////////////////////////////////////////////////////////////

int main() {

   string quote, book;

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   /////////////////////////////////////////////

   cout<<"What book was that quote from?"<<endl;

   getline(cin, book);

   cout<<endl;

   /////////////////////////////////////////////

   cout<<"What page was that quote from?"<<endl;

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   for (int i=0; i<quote.length(); i++) {

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   /////////////////////////////////////////////

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   bool isDog = false;

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           break;

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           for (int j=i+1; j<quote.length(); j++) {

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                   break;

               else if (quote[j] == 'o') {

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                           break;

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                   }

               }

           }

       }

   }

   

   if (isDog == true)

       cout<<"This includes 'd' 'o' 'g' in the quote";

   //////////////////////////////////////////////

   return 0;

}

3 0
3 years ago
When a circuit has more resistance, what happens to current flow ?
zloy xaker [14]
The relationship between resistance and the area of the cross section of a wire is inversely proportional . When resistance is increased in a circuit , for example by adding more electrical components , the current decreases as a result.
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