Answer:
#1. M NaOH = 0.1634 M
#2. M NaOH = 0.1464 M
#3. M NaOH = 0.1501 M
Explanation:
balanced reaction:
∴ molar mass KHP = 204.22 g/mol
#1:
∴ mass KHP = 0.5240 g
∴ volume NaOH = 15.7 mL = 0.0157 L
⇒ moles NaOH = (0.5240 g KHP)(mol/204.22 g KHP)(mol NaOH/mol KHP)
⇒ moles NaOH = 2.566 E-3 mol
⇒ M NaOH = (2.566 E-3 mol)/(0.0157 L) = 0.1634 M
#2:
∴ mass KHP = 0.5320 g
∴ volume NaOH = 17.8 mL = 0.0178 L
⇒ moles NaOH = 2.605 E-3 mol
⇒ M NaOH = 0.1464 M
#3:
∴ mass KHP = 0.5120 g
∴ volume NaOH = 16.7 mL = 0.0167 L
⇒ moles NaOH = 2.5071 E-3 mol
⇒ M NaOH = 0.1501 M