Is forms from coal, oil, and gas burning physical or chemical weathering

How many moles are in 175.9 grams of Pb3(PO4)2?

snow_lady [41]

Answer:

0.21674767727138733

Explanation:

Again I don't want to give an explanation right now because I can't exactly do that more than once. it hurts my child brain. And the fact that I just woke up.

8 0

3 years ago

Which of these is a mixture? a.water b.sugar c.carbon dioxide d.popcorn and salt

Dmitry_Shevchenko [17]

Popcorn and salt as the mixtures are substances which are formed by mixing other substances

7 0

3 years ago

Which scenario would result in a population growth of zero? Use this formula: population growth = (birth rate + immigration) – (

swat32

Answer:

12 individuals are born 10 individuals emigrate, 4 individuals die, 14 individuals immigrate, 0 individuals are born

Explanation:

From the formula:

Population growth = (birth rate + immigration) – (death rate + emigration)

= (b + i) - (d + e)

For the first option, b = 12, i = 0, d = 12, e = 12

population growth = (12+0) - (12+12) = -12

For the second option: b = 13, i = 0, d = 3, e = 16

population growth = (13+0) - (3+16) = -6

For the third option: b = 12, i = 20, d = 0, e = 8

population growth = (12+20) - (0+8) = 24

For the last option: b = 0, i = 14, d = 4, e = 10

population growth = (0+14) - (4+10) = 0

Hence, the last option is the correct option.

8 0

2 years ago

Read 2 more answers

Sodium peroxide (Na2O2) is often used in self-contained breathing devices, such as those used in fire emergencies, because it re

Anastaziya [24]

Answer:

725.15 L

Explanation:

The balanced chemical equation for the reaction between Na₂O₂ and CO₂ is the following:

Na₂O₂ + CO₂ → Na₂CO₃ + 1/2 O₂

From the stoichiometry of the reaction, 1 mol of Na₂O₂ reacts with 1 mol CO₂. So, the stoichiometric ratio is 1 mol Na₂O₂/1 CO₂.

Now, we convert the mass of reactants to moles by using the molecular weight (Mw) of each compound:

Mw (Na₂O₂) = (23 g/mol x 2) + (16 g/mol x 2) = 78 g/mol

moles Na₂O₂ = 96.7 g/(78 g/mol) = 1.24 mol Na₂O₂

Mw (CO₂) = 12 g/mol + (16 g/mol x 2) = 44 g/mol

moles CO₂ = 0.0755 g/(44 g/mol) = 1.71 x 10⁻³ mol CO₂

Now, we calculate the number of moles of CO₂ we need to completely react with the mass of Na₂O₂ we have:

1.24 mol Na₂O₂ x 1 mol CO₂/1 mol Na₂O₂ = 1.24 mol CO₂

In 1 L of respired air we have 1.71 x 10⁻³ mol CO₂ (0.0755 g), so we need the following number of liters to have 1.24 mol of CO₂:

1.24 mol CO₂ x 1 L/1.71 x 10⁻³ mol CO₂ = 725.15 L

4 0

3 years ago

Which formula correctly represents the composition of iron III oxide

nikitadnepr [17]

The answer to the question is- Fe2O3

6 0

2 years ago