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Sergeu [11.5K]
2 years ago
9

URGENT PLEASE HELP NOW!!

Chemistry
1 answer:
Katen [24]2 years ago
4 0

Answer:

A and B

Explanation:

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What is the oxidation state of co in [co(oh2)6]2?
Ahat [919]

Correct compound is [Co(H2O)6]^+3

The oxidation state of Co is +3

[Co(H2O)6]^+3

Let

 Co be x

 H2O = 0

 x + (0)6 = 3

 x = 3

What is oxidation state?

The oxidation state, commonly known as the oxidation number, is the potential charge that an atom would have if all of its bonds to other atoms were fully ionic. It describes the degree of atom oxidation within a chemical compound.The oxidation state may be positive, negative, or zero in theory.

The oxidation number, sometimes referred to as the oxidation state, is the total number of electrons that an atom gains or loses while uniting with another atom to form a chemical bond.

To learn more about oxidation state click the given link

brainly.com/question/8990767

#SPJ4

7 0
1 year ago
Aluminum sulfate, Al2(SO4)3, decomposes to form aluminum oxide,
konstantin123 [22]

Answer:

Al2(SO4)3 -> Al2O3+3SO3

Explanation:

No need of much explanation

During the time balancing the equations just see the no. of atoms on either side of the reaction I.e the reactant and product side make them equal by multiplying with some integers that's it!!

7 0
3 years ago
2. Write the chemical equation for the reaction NaOH Sodium Hydroxide AgNO3 Silver Nitrate
lys-0071 [83]

Answer:

AgNO3 + NaOH = AgOH + NaNO3.

Explanation:

<em><u>Balancing Strategies: In this reaction, the products are initially NaNO3 + AgOH. However the AgOH would break down into Ag2O and H2O. This would give us NaNO3 + Ag2O + H2O as our products for the overall reaction.</u></em>

<em><u>Balancing Strategies: In this reaction, the products are initially NaNO3 + AgOH. However the AgOH would break down into Ag2O and H2O. This would give us NaNO3 + Ag2O + H2O as our products for the overall reaction.However, the equation balanced here is the initial reaction which produces AgOH and NaNO3.</u></em>

8 0
3 years ago
g What is the half-life for a particular reaction if the rate law is rate = (1291 M⁻¹*min⁻¹)[A]² and the initial concentration o
Gnoma [55]

Answer:

t_{1/2}=3.10x10^{-3}min=0.186s

Explanation:

Hello,

In this case, for the calculation of the half-life for the mentioned reaction we first must realize that considering the units of the rate constant and the form of the rate law, it is a second-order reaction, therefore, the half-life expression is:

t_{1/2}=\frac{1}{k[A]_0}

Therefore, we obtain:

t_{1/2}=\frac{1}{1291\frac{1}{M*min}*0.250M}\\\\t_{1/2}=3.10x10^{-3}min=0.186s

Regards.

4 0
3 years ago
11.
Rom4ik [11]

Answer:

d

Explanation:

d. 1000.00  The fact that there is a decimal point is a sinal that the measurement was made down to past the ones position.  The 2 additional zeros signal that it was measured down to the hundreths position.

8 0
3 years ago
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