An aeroplane, flying in a straight line at a constant

how much centripetal force is needed to make a body of mass 0.5 kg to move in a circle of radius 50 cm with a speed 3ms-1

Alex17521 [72]

Answer:

9 N

Explanation:

The centripetal force F is F = mrω^2 = (mv^2)/r where m is mass, r is radius of the curve, ω is angular velocity and v is tangential velocity.

In this case, m = 0.5kg, r = 0.5m, v = 3m/s

So F = [0.5kg(3m/s)^2]/0.5m = 9kg-m/s^2 which is 9N

6 0

3 years ago

Read 2 more answers

What do these weapon stats mean?

kaheart [24]

Answer:

its sort of like how Pounds are measured in lbs

Explanation:

Pounds are measured in lbs when they dont sound anything similar, same thing applies to gun technology.

5 0

3 years ago

The x-coordinates of two objects moving along the x-axis are given as a function of time (t). x1= (4m/s)t x2= -(161m) + (48m/s)t

Kitty [74]

The two displacement functions are
x₁ = 4t
x₂ = -161 + 48t - 4t²
where
x₁, x₂ are in meters
t is time, s

The distance between the two objects is
x = x₁ - x₂
= 4t + 161 - 48t + 4t²
x = 4t² - 44t + 161

Write this equation in the standard form for a parabola.
x = 4[t² - 11t] + 161
= 4[ (t - 5.5)² - 5.5² ] + 161
x = 4(t-5)² + 40

Ths is a parabola that faces up and has its vertex (lowest point) at (5, 40).
Therefore the closest approach of the two objects is 40 m.
The graph of x versus t confirms the result.

Answer: The distance of the closest approach is 40 m.

5 0

3 years ago

#26 question

4vir4ik [10]

So, the time that taken for the astronaut to fall to the surface of the moon is <u>2.5 s.</u>

<h3>Introduction</h3>

Hi ! In this question, I will help you. In this question, you will learn about the fall time of the free fall motion. Free fall is a downward vertical motion without being preceded by an initial velocity. When moving in free fall, the time required can be calculated by the following equation:

$\sf{h = \frac{1}{2} \cdot g \cdot t^2}$

$\sf{\frac{2 \cdot h}{g} = t^2}$

$\boxed{\sf{\bold{t = \sqrt{\frac{2 \cdot h}{g}}}}}$

With the following condition :

t = interval of the time (s)
h = height or any other displacement at vertical line (m)
g = acceleration of the gravity (m/s²)

<h3>Problem Solving</h3>

We know that :

h = height = 5.00 m
g = acceleration of the gravity = 1.6 m/s²

What was asked :

t = interval of the time = ... s

Step by step :

$\sf{t = \sqrt{\frac{2 \cdot h}{g}}}$

$\sf{t = \sqrt{\frac{2 \cdot 5}{1.6}}}$

$\sf{t = \sqrt{6.25}}$

$\boxed{\sf{t = 2.5 \: s}}$

<h3>Conclusion</h3>

So, the time that taken for the astronaut to fall to the surface of the moon is 2.5 s.

Time that needed for hearing the splash of fallen rock in the well brainly.com/question/26485521
The speed of the object at a certain height (free fall motion) brainly.com/question/26377041
The relationship between acceleration and the change in velocity and time in free fall brainly.com/question/26486625

3 0

3 years ago

Two motors in a factory are running at slightly different rates. One runs at 825.0 rpm and the other at 786.0 rpm. You hear the

mixas84 [53]

Answer:

$T=1.54s$