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Rainbow [258]
2 years ago
9

In the SI system of units, the absolute temperature is measured to be 303 K Its value in Fahrenheit is a-) 76 F b)- 86F c)-79 F

d)- 82 F
Engineering
1 answer:
Alexeev081 [22]2 years ago
6 0

Answer:

The correct answer is option B i.e. 86 f

Explanation:

The freezing point of water is 32°f and boiling point is 212 °f.  Thus difference in boiling and freezing point is exactly come out to be 180°. therefore fahrenheit scale is 1/180 interval of both scale ( freezing and boiling point)

given data:

absolute temperature is 303 K

We know by general formula of temperature in fahrenheit

°F = \frac{9}{5} × (K-273) +32

°F = \frac{9}{5} × (303-273) +32

°F =  86 F

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Answer:

(a) The heat transferred is 2552.64 kJ    

(b) The entropy change of the mixture is 1066.0279 J/K

Explanation:

Here we have

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Number of moles of H₂ = 500/2.01588  = 248 moles

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At constant pressure, the temperature is doubled, therefore

T₂ = 600 K

If we assume constant specific heat at the average temperature, we have

Heat supplied = m₁×cp₁×dT₁ + m₂×cp₂×dT₂

 cp₁ = Specific heat of hydrogen at constant pressure = 14.50 kJ/(kg K

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Heat supplied = 0.5×14.50×300 K+ 1.2×1.049×300 =  2552.64 kJ    

b)  \Delta S = - R(n_A \times lnx_A + n_B \times ln x_B)

Where:

x_A and x_B are the mole fractions of Hydrogen and nitrogen respectively.

Therefore, x_A = 248 /(248 + 42.8) = 0.83

x_B = 42.8/(248 + 42.8) = 0.1472

∴ \Delta S = - 8.3145(248 \times ln0.83 + 42.8 \times ln 0.1472) =  1066.0279 J/K

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