Answer:
P= 5.5 bar
Explanation:
Given that
L= 4000 m
d= 0.2 m
Friction factor(F) = 0.01
speed V= 2 m/s
Head = 5 m
Head loss due to friction



So the total head(H) = 5 + 40.77 + 10.3 =56.07
Where 10.3 m is the atmospheric head.
We know that
P=ρ g H
So total Pressure
P= 1000 x 9.81 x 56.07 Pa

P= 5.5 bar
youn need to use your hands
Answer: The net force in every bolt is 44.9 kip
Explanation:
Given that;
External load applied = 245 kip
number of bolts n = 10
External Load shared by each bolt (P_E) = 245/10 = 24.5 kip
spring constant of the bolt Kb = 0.4 Mlb/in
spring constant of members Kc = 1.6 Mlb/in
combined stiffness factor C = Kb / (kb+kc) = 0.4 / ( 0.4 + 1.6) = 0.4 / 2 = 0.2 Mlb/in
Initial pre load Pi = 40 kip
now for Bolts; both pre load Pi and external load P_E are tensile in nature, therefore we add both of them
External Load on each bolt P_Eb = C × PE = 0.2 × 24.5 = 4.9 kip
So Total net Force on each bolt Fb = P_Eb + Pi
Fb = 4.9 kip + 40 kip
Fb = 44.9 kip
Therefore the net force in every bolt is 44.9 kip
Answer:
If you mean two sides are 7 and two sides are 14 then you'd have 42
and for the second you'd have 14
Explanation:
7 + 7 = 14, 14 + 14 = 28, 14 + 28 = 42
3 + 3 = 6, 4 + 4 = 8, 8 + 6 = 14