Answer:
The final pressure is 3.16 torr
Solution:
As per the question:
The reduced pressure after drop in it, P' = 3 torr = 
At the end of pumping, temperature of air, 
After the rise in the air temperature, 
Now, we know the ideal gas eqn:
PV = mRT
So
(1)
where
P = Pressure
V = Volume
R = Rydberg's constant
T = Temperature
Using eqn (1):
Now, at constant volume the final pressure, P' is given by:
Answer:
A) ν = 0.292
B) ν = 0.381
Explanation:
Poisson's ratio = - (Strain in the direction of the load)/(strain in the direction at right angle to the load)
In axial tension, the direction of the load is in the length's direction and the direction at right angle to the load is the side length
Strain = change in length/original length = (Δy)/y or (Δx)/x or (ΔL/L)
A) Strain in the direction of the load = (2.49946 - 2.5)/2.5 = - 0.000216
Strain in the direction at right angle to the load = (7.20532 - 7.2)/7.2 = 0.0007389
Poisson's ratio = - (-0.000216)/(0.0007389) = 0.292
B) Strain in the direction of the load = (2.09929 - 2.1)/2.1 = - 0.0003381
Strain in the direction at right angle to the load = (5.30470 - 5.3)/5.3 = 0.0008868
Poisson's ratio = - (-0.0003381)/(0.0008868) = 0.381
Answer:
It’s cool I’d say 8/10 I guess
Explanation:
Answer:
Stress corrosion cracking
Explanation:
This occurs when susceptible materials subjected to an environment that causes cracking effect by the production of folds and tensile stress. This also depends upon the nature of the corrosive environment.
Factors like high-temperature water, along with Carbonization and chlorination, static stress, and material properties.
