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Anni [7]
3 years ago
12

Correct me if I'm wrong, but if you put a glass of water outside when the relative humidity is 100%, the will not evaporate...ri

ght?
Physics
2 answers:
Llana [10]3 years ago
7 0

Answer:

No, it's not going to evaporate.

rewona [7]3 years ago
5 0
If the humidity is 100% then it will not evaporate because 100% humidity means that the air is saturated with water vapour.
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Because of your physics background, you have been able to get a job with a company devising stunts for an upcoming adventure mov
GaryK [48]

Answer:

16.35 m/s^{2}

Explanation:

To obtain the minimum acceleration,  we know that normal force is equivalent to force in x-axis

Fx=N

#Frictional force is calculated using the formula:

F_r=\mu N-mg=0

but N= ma in this case acceleration in x axis hence

\mu_{max}m_a_x-mg=0\\a_x=\frac {g}{mu_s} =\frac {9.81}{0.60}=16.35 m/s^{2}

3 0
3 years ago
The police department is excited to have some new motorcycle units. One officer said that these motorcycles can go from 0 miles
nikklg [1K]
The officer is describing the motorcycle's acceleration. Of course when the bike goes from 0 to 80 in 6 seconds the police officer himself is left lying flat on his back in the parking lot.
7 0
3 years ago
A 5kg block of iron is heated to 800degree C.it is placed in a tub containing 2litre of water at 15degree C.Assuming all the wat
icang [17]
Te correct answer is a
6 0
3 years ago
Would the frequency of the angular simple harmonic motion (SHM) of the balance wheel increase or decrease if the dimensions of t
storchak [24]

Answer:

Yes the frequency of the angular simple harmonic motion (SHM) of the balance wheel increases three times if the dimensions of the balance wheel reduced to one-third of original dimensions.

Explanation:

Considering the complete question attached in figure below.

Time period for balance wheel is:

T=2\pi\sqrt{\frac{I}{K}}

I=mR^{2}

m = mass of balance wheel

R = radius of balance wheel.

Angular frequency is related to Time period as:

\omega=\frac{2\pi}{T}\\\omega=\sqrt{\frac{K}{I}} \\\omega=\sqrt{\frac{K}{mR^{2}}

As dimensions of new balance wheel are one-third of their original values

R_{new}=\frac{R}{3}

\omega_{new}=\sqrt{\frac{K}{mR_{new}^{2}}}\\\\\omega_{new}=\sqrt{\frac{K}{m(\frac{R}{3})^{2}}}\\\\\omega_{new}={3}\sqrt{\frac{K}{mR^{2}}}\\\\\omega_{new}={3}\omega

5 0
3 years ago
A 10,000kg space ship is orbiting the moon with a radius of 25km from the ship to the center of the moon. It's tangential speed
galina1969 [7]

Answer:

False

Explanation:

ac = v^2/r

acceleration is not dependent on the mass of the orbiting object.

3 0
3 years ago
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