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hoa [83]
3 years ago
10

Which microscope has the highest potential magnification? comparison microscope scanning electron microscope compound microscope

stereoscopic microscope?
Physics
2 answers:
sveta [45]3 years ago
4 0

Answer: electron microscope

Explanation:

An electron microscope is a microscope which uses an electron beam to illuminate a specimen and it creates an enlarged image of that specimen. This microscope exhibit a very high resolving power as compared to light microscopes. This is capable of obtaining very high magnification. Some of the electron microscopes can magnify an image of the specimen upto 2 million times.

TiliK225 [7]3 years ago
3 0

The answer is the electron microscope. It is a kind of microscope that uses electrons to light a sample and make an enlarged image. These kinds of microscopes have much better determining power than light microscopes and can get much higher magnifications.

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Eric is creating a timeline of the formation of the solar system. Which sequence best describes the formation of the solar syste
vlada-n [284]

The answer is C. nebular are star nurseries. When the massive gas being collapsing in its own weight. Local areas of gas begin to coalesce under gravity. Due to enormous pressure, nuclear fusion begins and a protostar is formed. The protostar grows into the sun as more hydrogen fuses at the core. The planetesimal materials at the edges of the protostellar discs coalesce to form planets that orbit the star.

3 0
3 years ago
Read 2 more answers
How would the terminal velocity of a piece of tissue paper compare to the terminal velocity of a rock?
matrenka [14]

Answer: Rock require larger drag force and to achieve it rock need to move at a very high terminal velocity.  

Explanation: Terminal velocity is defined as the final velocity attained by an object falling under the gravity. At this moment weight is balanced by the air resistance or drag force and body falls with zero acceleration i.e. with a constant velocity.

Case 1: Terminal velocity of a piece of tissue paper.

The weight of tissue paper is very less and it experiences an air resistance while falling downward under the effect of gravity.

Downward gravitational force, F = mg

Upward air resistance or friction or drag force will be f_{1}

So, paper will attain terminal velocity when mg =  f_{1}

Case 2: Rock is very heavy and require larger air resistance to balance the weight of rock relative to the tissue paper case.

Downward force on rock, F = Mg

Drag force = f_{2}

Rock will attain terminal velocity when Mg = f_{2}

Mg > mg

so, f_{2} > f_{1}

And rock require larger drag force and to achieve it rock need to move at a very high terminal velocity.  

5 0
3 years ago
. A dog walks 14 m to the east and then 20 m back to the west. What is the distance? What is the displacement?​
Crank

Answer:

Hi...

14-20=-6...displacement

14+20=34...distance

3 0
2 years ago
10. Solve the following numerical problems
frosja888 [35]

Answer:

\boxed {\boxed {\sf 120 \ Joules}}

Explanation:

Work is equal to the product of force and distance.

W=F*d

The force is 8 Newtons and the distance is 15 meters.

F= 8 \ N \\d= 15 \ m

Substitute the values into the formula.

W= 8 \ N * 15 \ m

Multiply.

W= 120 \ N*m

  • 1 Newton meter is equal to 1 Joule
  • Our answer of 120 N*m equals 120 J

W= 120 \ J

The work done is <u>120 Joules</u>

3 0
3 years ago
A string that passes over a pulley has a 0.341 kg mass attached to one end and a 0.625 kg mass attached to the other end. The pu
dalvyx [7]

Answer:

The frictional torque is \tau  = 0.2505 \ N \cdot m

Explanation:

From the question we are told that

   The mass attached to one end the string is m_1 =  0.341 \ kg

   The mass attached to the other end of the string is  m_2 =  0.625 \ kg

    The radius of the disk is  r = 9.00 \ cm  = 0.09 \ m

At equilibrium the tension on the string due to the first mass is mathematically represented as

      T_1 =  m_1 *  g

substituting values

      T_1 =  0.341 * 9.8

      T_1 =  3.342 \ N

At equilibrium the tension on the string due to the  mass is mathematically represented as

      T_2 =  m_2 *  g

     T_2 = 0.625 * 9.8

      T_2 = 6.125 \ N

The  frictional torque that must be exerted is mathematically represented as

      \tau  =  (T_2 * r ) - (T_1 * r )

substituting values  

     \tau  =  ( 6.125 * 0.09 ) - (3.342  * 0.09 )

     \tau  = 0.2505 \ N \cdot m

5 0
3 years ago
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