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hoa [83]
3 years ago
10

Which microscope has the highest potential magnification? comparison microscope scanning electron microscope compound microscope

stereoscopic microscope?
Physics
2 answers:
sveta [45]3 years ago
4 0

Answer: electron microscope

Explanation:

An electron microscope is a microscope which uses an electron beam to illuminate a specimen and it creates an enlarged image of that specimen. This microscope exhibit a very high resolving power as compared to light microscopes. This is capable of obtaining very high magnification. Some of the electron microscopes can magnify an image of the specimen upto 2 million times.

TiliK225 [7]3 years ago
3 0

The answer is the electron microscope. It is a kind of microscope that uses electrons to light a sample and make an enlarged image. These kinds of microscopes have much better determining power than light microscopes and can get much higher magnifications.

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For the ballistic missile aimed to achieve the maximum range of 9500 km, what is the maximum altitude reached in the trajectory
liraira [26]

Explanation:

The range <em>R</em> of a projectile is given the equation

R = \dfrac{v_0^2}{g}\sin{2\theta}

The maximum range is achieved when \theta = 45° so our equation reduces to

R_{max} = \dfrac{v_0^2}{g}

We can solve for the initial velocity v_0 as follows:

v_0^2 = gR_{max} \Rightarrow v_0 = \sqrt{gR_{max}}

or

v_0 = \sqrt{(9.8\:\text{m/s}^2)(9.5×10^6\:\text{m})}

\:\:\:\:\:\:\:=9.6×10^3\:\text{m/s}

To find the maximum altitude H reached by the missile, we can use the equation

v_y^2 = v_{0y}^2 - 2gy = (v_0\sin{45°})^2 - 2gy

At its maximum height H, v_y = 0 so we can write

0 = (v_0\sin{45°})^2 - 2gH

or

H = \dfrac{(v_0\sin{45°})^2}{2g}

\:\:\:\:\:\:= \dfrac{[(9.6×10^3\:\text{m/s})\sin{45°}]^2}{2(9.8\:\text{m/s}^2)}

\:\:\:\:\:\:= 2.4×10^6\:\text{m}

7 0
2 years ago
A teacher pushed a 98 newton desk across a floor for a distance of 5 meters. He exerted a horizontal force of 20 N for four seco
Pie

Answer:

First let's find the work.

Work = Force*Displacement

= 20*5

= 100 Joules

Power = Work/Time

= 100/4

= 25 Watts

7 0
3 years ago
All vehicles are required to stop within how many feet of a railroad crossing when a train is approaching
Lunna [17]
All vehicles are required to stop within 15 FEET of the railroad crossing when a train is approaching.
8 0
4 years ago
Acceleration Practice
Trava [24]

Answer:

0.85 m/s²

Explanation:

Acceleration is change in velocity over change in time. In mathematically, it can be expressed as:

\displaystyle{\vec{a} = \dfrac{\Delta \vec{v}}{\Delta t} = \dfrac{\vec v_2 - \vec v_1}{t_2-t_1}}

Our final velocity is given to be 17 m/s in 20 seconds. Initial velocity is at starting point which is 0 m/s in 0 second. Therefore:

\displaystyle{\vec{a} = \dfrac{\Delta \vec{v}}{\Delta t} = \dfrac{17-0}{20-0}}\\\\\displaystyle{\vec{a} = \dfrac{\Delta \vec{v}}{\Delta t} = \dfrac{17}{20}}\\\\\displaystyle{\vec{a} = \dfrac{\Delta \vec{v}}{\Delta t} = 0.85 \ \, \sf{m/s^2}}

Therefore, the acceleration of a horse from starting point to 17 m/s in 20 seconds is 0.85 m/s²

8 0
2 years ago
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ch4aika [34]

Answer:

i think answer b

Explanation:

8 0
3 years ago
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