<span>The Earth’s internal "((HEAT))" source provides the energy for our dynamic planet, providing it with the driving force for on-going disastrous events such as earthquakes and volcanic eruptions and for plate-tectonic motion. </span>
Answer:
The frequency of oscillations is 7 Hz
Explanation:
Given;
mass of car, = 1700 kg
mass of driver, = 66 kg
compression of the spring, x = 5mm = 0.005 m
The frequency of the oscillation is given as;
where;
k is force constant
m is the total mass of the car and the driver
m = 1700 kg + 66 kg = 1766 kg
Weight of the car and the driver;
W = mg
W = 1766 x 9.8
W = 17306.8 N
Apply hook's law, to determine the force constant;
F = kx
W = F
Thus, k = W/x
k = 17306.8 / 0.005
k = 3461360 N/m
Now, calculate the frequency
Therefore, the frequency of oscillations is 7 Hz
Answer:
a) L= 3568 m
b) 9×10^{-5} sec
c) 8.92×10^{-5} sec
Explanation:
runway length on the Earth L_o = 3600 m
Speed of the spacecraft flying past v= 4.00×10^7 m/s
then Einstein's length contraction theory,
Solving we get L= 3568 m
b) Time interval for an observer on earth when the spacecraft is directly over one end of the runway until it is directly over the other end.
L_o= 3600 m
speed v= 4.00×10^7 m/s
Then time interval Δt = L_o/v= = 9×10^{-5} sec
c) for the pilot the time interval will be
Δt_o = L/v = = 8.92×10^{-5} sec
Answer:
14740.7 m
Explanation:
G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²
M = Mass of black hole =
c = Speed of light =
Schwarzschild radius is given by
The radius of the event horizon of the black hole is 14740.7 m
Your answer would be force