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s2008m [1.1K]
3 years ago
8

What is the time traveled by a pulse over a distance of lcm in air (n=1) and in 1cm of glass (n 1.5)? What is the difference in

picoseconds?
Physics
1 answer:
Salsk061 [2.6K]3 years ago
8 0

Answer: in air 33.33 ps and in the glass 50 ps: so the difference 16.67 ps

Explanation: In order to calculate the time for a pulse travellin in air  and in a glass we have to consider the expresion of the speed given by:

v= d/t  v the speed in a medium is given by c/n where c and n are the speed of light and refractive index respectively.

so the time is:

t=d/v=d*n/c

in air

t=0.01 m*1/3*10^8 m/s= 33.33 ps

while for the glass

t=0.01 m*1.5* 3* 10^8 m/s= 50 ps

Finally the difference is (50-33.33)ps = 16.67 ps

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Answer:

B. It will point to the left and oppose the initial applied field

Explanation:

Let the charge be positive and  and electric field be towards right . Charge will move towards right in the field due to which positive charge will accumulate towards right and excess of positive charge will lie there . This new charge distribution will create a field towards the left which is opposite to external electric field.

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A car is driving directly north on the freeway at a speed of 91 km/h and a truck is leaving the freeway driving 56 km/h in a dir
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Answer:

v = 49.69 km/hr

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3 years ago
If the size of the charge value is tripled for both of twopoint charges maintained at a constant separation, the mutual forcebet
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An electron is trapped in a one-dimensional infinite well of width 340 pm and is in its ground state. What are the (a) longest,
Nesterboy [21]

Answer:

(a) 1.2703×10⁻⁷ m

(b) 4.7636×10⁻⁸ m

(c) 2.5406×10⁻⁸ m

Explanation:

Given:

Width of the infinite well, L = 340 pm = 340×10⁻¹² m.

The formula for energy of the electron in nth state is:

E_n=\frac {n^2\times h^2}{8mL^2}

The expression for the difference in energy between the levels having quantum numbers n(initial) to n(final) is:

\Delta E_n=\frac {({n_f}^2-{n_i}^2)\times h^2}{8mL^2}

According to Planks theory:

E = hv

where, v is the frequency

Also,

Frequency×Wavelength = Speed of light

So,

E=\frac {hc}{\lambda}

\lambda=\frac {hc}{E}

Also,  using energy from above formula as:

\lambda=\frac {hc}{\frac {({n_f}^2-{n_i}^2)\times h^2}{8mL^2}}

\lambda=\frac {c\times {8mL^2}} {({n_f}^2-{n_i}^2)\times h}}

For longest wavelength ni = 1 and nf = 2

m= mass of the electron = 9.1 ×10⁻³¹kg

c = 3×10⁸m/s

h = 6.625×10⁻³⁴J.sec

\lambda_{Longest}=\frac {3\times 10^8\times {8\times 9.1\times 10^{-31}(340\times 10^{-12})^2}} {({2}^2-{1}^2)\times 6.625\times 10^{-34}}}

<u>Longest wavelength = 1.2703×10⁻⁷ m</u>

For second longest wavelength ni = 1 and nf = 3

\lambda_{Second\ Longest}=\frac {3\times 10^8\times {8\times 9.1\times 10^{-31}(340\times 10^{-12})^2}} {({3}^2-{1}^2)\times 6.625\times 10^{-34}}}

<u>Second longest wavelength = 4.7636×10⁻⁸ m</u>

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\lambda_{Third\ Longest}=\frac {3\times 10^8\times {8\times 9.1\times 10^{-31}(340\times 10^{-12})^2}} {({4}^2-{1}^2)\times 6.625\times 10^{-34}}}

<u>Third longest wavelength = 2.5406×10⁻⁸ m</u>

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