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dangina [55]
3 years ago
13

Geraldo wants to model the effect of acids on the pH of

Chemistry
2 answers:
stira [4]3 years ago
7 0

Answer:

Q:Which pollutant should Geraldo add to the water?

A: Pesticide.

Q.What will the pH reading be after Geraldo adds the pollutant?

A.less than 6.65.

Explanation:

got it right on edge :)

Furkat [3]3 years ago
6 0

Answer: Pesticide and less than 6.65

Explanation:

E2020

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The volume of 0.05 M H2SO4 is needed to completely neutralise 15ml of 0.1 M NaOH solution is
Feliz [49]
V(NaOH)=15 mL =0.015 L
C(NaOH)=0.1 mol/L
C(H₂SO₄)=0.05 mol/L

2NaOH + H₂SO₄ = Na₂SO₄ + 2H₂O

n(NaOH)=V(NaOH)C(NaOH)=2n(H₂SO₄)
n(H₂SO₄)=V(H₂SO₄)C(H₂SO₄)

V(NaOH)C(NaOH)=2V(H₂SO₄)C(H₂SO₄)

V(H₂SO₄)=V(NaOH)C(NaOH)/{2C(H₂SO₄)}

V(H₂SO₄)=0.015*0.1/{2*0.05}=0.015 L = 15 mL
5 0
3 years ago
Which corresponds to the composition of the ion typically formed by magnesium?
nekit [7.7K]
The ion composition of Magnesium is 12,10, 2+.
Magnesium is a chemical element with symbol Mg and an atomic number 12, it has 12 protons, and 12 electrons with a chemical configuration of 2:8:2. It requires to loose two electrons to form a stable configuration forming a cation (positively charged ion) with a charge of +2 and  a configuration of 2:8 ( 12 protons and 10 electrons).
3 0
3 years ago
Prokaryotes and Eukaryotes both fall in<br> the category of living things.<br> True<br> False
WITCHER [35]

Answer:

False

Explanation:

Prokaryotes are a single-celled organism that has not specialized organelles. This consists of bacteria and cyanobacteria.

Eukaryotes are a cell or cells in which the genetic material of DNA is in the form of chromosomes. This includes all living things other than eubacteria and archaebacteria.

<u><em>Hope this helps!</em></u>

<u><em>Please mark brainliest! </em></u>

5 0
3 years ago
Calculate the PH of a solution 0.030 MH2SO4
Zinaida [17]

Answer:

pH= 2- log3

Explanation:

H2SO4 + H2O -> HSO4^(-) + H30^(+)

0.03M ___ ___

___ 0.03M 0.03M

H30^(+) : C = 0.03M

pH= - log( [H3O^(+)] ) => pH= - log {3× 10^(-2)} => pH = 2 - log3

4 0
3 years ago
Calculate the ph of a 0.40 m solution of sodium benzoate (nac6h5coo) given that the ka of benzoic acid (c6h5cooh) is 6.50 x 10-5
asambeis [7]
Hello!

The dissociation reaction for Benzoic Acid is the following:

C₆H₅COOH + H₂O ⇄ C₆H₅COO⁻ + H₃O⁺

The Ka expression is the following and we clear for the concentration of H₃O⁺(X) assuming that the dissociation is little so we can rule it out in the denominator of the equation:

Ka= \frac{[C_6H_5COO^{-}]*[H_3O^{+}] }{[C_6H_5COOH]}=\frac{X*X }{0,40 -X}  (assume: 0,40-X\approx0,40)\\  \\ X= \sqrt{0,40*6,50*10^{-5} }=0.00510M \\  \\ pH=-log([H_3O^{+}]=2,29

So, the pH of this Benzoic Acid solution is 2,29

Have a nice day!


3 0
3 years ago
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