Answer:
pH = 10
The solution is basic.
Explanation:
A solution contains 1 × 10⁻⁴ M OH⁻ ions. First, we will calculate the pOH.
pOH = -log [OH⁻]
pOH = -log 1 × 10⁻⁴
pOH = 4
We can find the pH of the solution using the following expression.
pH + pOH = 14.00
pH = 14.00 - pOH = 14.00 - 4 = 10
Since the pH > 7, the solution is basic.
Answer:
Final concentrations:
Cu²⁺ = 0
Al³⁺ = 3.13 mmol/L = 84.51 mg/L
Cu = 4.7 mmol/L = 300 mg/L
Al = 0.57 mmol/L = 15.49 mg/L
Explanation:
2Al (s) + 3Cu²⁺ (aq) → 2Al³⁺ (aq) + 3Cu (s)
Al: 27 g/mol ∴ 100 mg = 3.7 mmol
Cu: 63.5 g/mol ∴ 300 mg = 4.7 mmol
3 mol Cu²⁺ _______ 2 mol Al
4.7 mmol Cu²⁺ _____ x
x = 3.13 mmol Al
4.7 mmol of Cu²⁺ will be consumed.
3.13 mmol of Al will be consumed.
4.7 mmol of Cu will be produced.
3.13 mmol of Al³⁺ will be produced.
0.57 mmol of Al will remain.
The two s Orbital electrons and one d orbital electron, are the electrons that are lost by an atom of Iron when it forms the Fe3 + ion.
Answer:
B.Self powered
Explanation:
They move by themselves.Hope this answer helps you ;)
The answer is A. The element is sodium (Na) and is highly reactive
