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MaRussiya [10]
2 years ago
6

How many moles of C3H8 will be produced from 75 moles of CO2?C3H8 + 5 O2 → 3 CO2 + 4 H2O

Chemistry
1 answer:
levacccp [35]2 years ago
8 0

25 moles of C3H8 will be produced from 75 moles of CO2.

<h3>Mole calculation</h3>

To find the value of moles of a product from the number of moles of a reactant, it is necessary to observe the stoichiometric ratio between them:

                             C_3H_8 + 5 O_2 = > 3 CO_2 + 4 H_2O

Analyzing the reaction, it is possible to see that the stoichiometric ratio is 1:3, so we can perform the following expression:

                           

                            C3H8                CO2

                                      \frac{1mol}{xmol} =\frac{3mol}{75mol}

                                         x = 25mol

So, 25 moles of C3H8 will be produced from 75 moles of CO2.

Learn, more about mole calculation in: brainly.com/question/2845237

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Why is not used at nuclear plant as a soverce for electrical energy
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7 0
2 years ago
Match the condensed structural diagrams with the correct names
AleksAgata [21]

Answer:

Here's what I get  

Explanation:

1. Names

I.   CH₃-CH₂-COOH              = 49. propanoic acid

II.  CH₃-CH₂-OH                    = 46. ethanol

III. CH₃-COO-CH₂-CH₂-CH₃ = 47. propyl ethanoate

IV. H-O-CH₂-CH₂-CH₃         = 48. propan-1-ol

V.  H-COO-CH₃                    = 51. methyl methanoate

VI. CH₃-COOH                      = 50. ethanoic acid

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6 0
3 years ago
How can I calculate the mass percent of carbon, nitrogen and oxygen in caffeine, C8H10N4O2.
Ahat [919]

You must first calculate the total weight of 1 mole of the substance. You do this by finding the molar weights on the periodic table of each of the elements in the compound:

8(12.01g)+10(1.008g)+4(14.007g)+2(15.999g)=96.08g+10.08g+56.028g+31.998g=194.186g

So now we take the amount of each element that is given in the compound and divide it by the total mass of the compound:

Carbon: 96.08g

\frac{96.08g}{194.186g}= 0.49478=49.48

Carbon = 49.48%

Nitrogen: 56.028g

\frac{56.028g}{194.186g}=0.28853=28.85

Nitrogen = 28.85%

Oxygen: 31.998g

\frac{31.998g}{194.186g} =0.16478=16.48

Oxygen = 16.48%

8 0
3 years ago
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