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3 years ago

Small pieces of sand hitting the side of a mountain and weathering the rock is an example of what type of weathering?

Physics

1 answer:

Nataly [62]3 years ago

8 0

Answer: This is MECHANICAL type of weathering.

Explanation:

Weathering is defined as the process by which rocks breakdown into smaller quantities due to different atmospheric and biological activities.

There are different types of weathering which include:

--> MECHANICAL WEATHERING: This type of weathering is also called physical weathering. Here, rocks are being broken down into smaller pieces but the mineral composition of the rock remains the same. This type of weathering can occur in two ways:

• By Ice wedging: this is one of the easiest ways rocks can be broken into smaller pieces. It occurs at the earth polar regions (climate that regularly cycles above and below the freezing point) and in areas of higher elevations such as the mountains. Ice wedging of rocks occurs when water seeps into cracks, it freezes and expands. This results in wedging (splitting) the rocks apart with repeated freezing.

• By Abrasion: this is another form in which mechanical weathering occurs. Abrasion occurs when strong winds carrying pieces of sand sandblast mountain surfaces. Also moving water, gravity, biological activities can cause abrasion of rock surfaces leading to its weathering.

Therefore, small pieces of sand hitting the side of a mountain and weathering the rock is an example of mechanical weathering by abrasion.

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3 years ago

A small 0.14 kg metal ball is tied to a very light (essentially massless) string that is 0.9 m long. The string is attached to t

Vsevolod [243]

Answer:

a) v=2.743m/s

b) $a_c = 8.363m/s^2$

c) T=2.543N

Explanation:

First, calculate the height of the ball at the starting point:

$y' = 0.9cos(55)$

$y' = 0.516$

At this point, just in the moment the ball is released, all the energy of the system is potencial gravitational energy. When it is at the bottom all the potencial energy is transformed into kinetic energy:

$E_p=E_k\\mgh=\frac{mv^2}{2}$

Solving for v:

$v=\sqrt{2gh}$

if h is the height loss: (l-y')

v=2.743m/s

The centripetal acceleration is the acceleration caused by the tension force exercised by the string, and is pointing outside of the trayectory path (at the lowest point, directly dawn):

$a_c=\frac{v^2}{r}$

$a_c = 8.363m/s^2$

To calculate tension, just make the free body diagram of forces in the ball, noticing the existence of the centripetal acceleration:

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4 years ago

Instruction Active

nikklg [1K]

If the distance between two objects decrease and the masses of the objects remain the same, then the force of gravity between the two objects

Answer:

increases

Explanation:

The formula of gravitational force is given as:

F=G Mm/r^2

G = gravitational constant

M, m = Masses of two different objects in which the force is acting.

r = distance between both the objects.

As we can see from the formula that the force of gravity is inversely proportional to the square of the distance between both objects.

When the distance between both objects with the same masses decreases the gravitational force between them increases. Hence the correct answer is option B.

Illamends had the exact same answer from a similar question. Credit goes to her

4 0

2 years ago

Read 2 more answers