Question

up off the ground a distance of 0.31 m before releasing her. Assume the partner’s velocity is zero at the beginning and the end of the lift. The acceleration of gravity is 9.8 m/s 2 . If he does this 30 times, how much work has he done? Answer in units of J.

Answer 1

Answer:

work done he has done is equal to 6452.712 J

Explanation:

given,                                                    

Assume the mass of the cheerleader be equal to 70.8 kg

she is lift up off to the height of 0.31 m              

acceleration due to gravity = 9.8 m/s²                        

number of time she was lift = N = 30 times

work done = N W                            

W = m g h                                          

work done = N m g h                    

work done = 30 x 70.8 x 9.8 x 0.31

                   = 6452.712 J                  

hence, work done he has done is equal to 6452.712 J