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Flauer [41]
4 years ago
7

Question 5

Chemistry
1 answer:
Igoryamba4 years ago
4 0

Answer: The pressure inside the cylinder will be 2.78 atm. The pressure can be calculated using the Ideal Gas Equation which relates the pressure, volume, temperature, and amount of gas to each other.  

Further Explanation

The Ideal Gas Equation is:  

PV = nRT

where:

P - pressure (in atm)

V - volume (in L)

n - amount of gas (in moles)

R - universal gas constant 0.08206 \frac{L-atm}{mol-K}

T - temperature (in K)

In the problem, we are given the values:

P = ?

V = 15.0 L (3 significant figures)

n = 1.75 moles N2 ( 3 significant figures)

T = 17.50 degrees Celsius (4 significant figures)

We need to convert the temperature to Kelvin before we can use the Ideal Gas Equation. The formula to convert from degree Celsius to Kelvin is:

Temperature \ in \ Kelvin = Temperature\ in \ Celsius \ + \ 273.15

Therefore, for this problem,

Temperature\ in \ K = 17.50 +273.15\\Temperature\ in \ K = 290.65

Solving for P using the Ideal Gas Equation:

P = \frac{nRT}{V} \\P = \frac{(1.75\ mol) \ (0.08206 \ \frac{L-atm}{mol - K}) \ (290.65\ K) \ }{15.0 \ L} \\P = 2.78\ atm

The least number of significant figures is 3, therefore, the final answer must have only 3 significant figures (P = 2.78 atm).

Learn More

1. Learn more about Boyle's Law brainly.com/question/1437490  

2. Learn more about Charles' Law brainly.com/question/1421697

3. Learn more about Avogadro's Law brainly.com/question/1964205

Keywords: Ideal Gas Law, Gas Pressure

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f is the frequency

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 E  =  6.63 x 10⁻³⁴m²kg/s x 8.4 x 10¹⁴Hz

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2.

Given parameters:

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Unknown:

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The frequency of a wave can be determined using the expression;

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f  is the frequency

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4 years ago
Which statement about atoms is correct
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I've also corrected the other statements

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177.277amu

Explanation:

the total occuring isotopes for Hafnium is =6.

First isotope had an atomic weight of 173.940amu

Second isotope =175.941amu

Third isotope =176.943amu

Fourth isotope=177.944amu

Fifth isotope. =178.946amu

sixth isotope .179.947amu

<em>Avera</em><em>ge</em><em> </em><em>ato</em><em>mic</em><em> </em><em>wei</em><em>ght</em><em> </em><em>of</em><em> </em><em>Haf</em><em>nium</em><em>=</em><em> </em><em>sum</em><em> </em><em>of</em><em> </em><em>all</em><em> </em><em>the </em><em>atomi</em><em>c</em><em> </em><em>weights</em><em> </em><em>of</em><em> </em><em>the</em><em> </em><em>iso</em><em>topes</em><em>/</em><em> </em><em>Tota</em><em>l</em><em> </em><em>occu</em><em>ring</em><em> </em><em>isotopes</em>

Thus, 173.940amu+175.941amu+176.943amu+177.944amu+178.946amu+179.947amu.= 1063.661amu

Average atomic weight= 1063.661amu /6 = 177.2768333amu

= 177.277amu to 3 decimal places.

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