Question

The path of a softball thrown by maddie forms a parabola wirh the equation y=-3/2401(x-49)^2+8.5 how far does the ball travel vefore it again reaches the same height from which it was thrown

Answer 1

Answer:

The distance travelled by ball is 98 units before it again reaches the same height from which it was thrown.

Step-by-step explanation:

The given parabolic equation is

$y=-\frac{3}{2401}(x-49)^2+8.5$

Where, h is height of ball after covering x distance horizontally.

Put x=0, to find initial height of the ball.

$y=-\frac{3}{2401}(0-49)^2+8.5$

$y=-3+8.5$

$y=5.5$

Put y=5.5 in the given equation and find the values of x at which the height of ball is 5.5.

$5.5=-\frac{3}{2401}(x-49)^2+8.5$

$\frac{3}{2401}(x-49)^2=-5.5+8.5$

$\frac{3}{2401}(x-49)^2=3$

$(x-49)^2=2401$

Take square root both sides.

$x-49=\pm 49$

$x=\pm 49+49$

$x=0,98$

The height of ball is 5.5 at x=0 and x=98.

Therefore distance travelled by ball is 98 units before it again reaches the same height from which it was thrown.